Compare how you would model and record finding the sum and difference of two rocks weighing 2/8 & 3/8 of a pound

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

7 0

Sum = 2/8 + 3/8 = (2+3)/8 = 5/8 pounds

Difference = 3/8 - 2/8 = (3-2)/8 = 1/8 pounds

You might be interested in

Subtract: 4x/x^2-25 - 2/x^2+2x-15

Alex777 [14]

Answer: $\dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}$

Step-by-step explanation:

Given

Subtract the expression

$\Rightarrow \dfrac{4x}{x^2-25}-\dfrac{2}{x^2+2x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{x^2+5x-3x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{(x+5)(x-3)}\\\\\text{Take the LCM and subtract}\\\\\Rightarrow \dfrac{4x(x-3)-2(x-5)}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-12x-2x+10}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}$

4 0

3 years ago

|0.7x+5|>6.7 Help plz

Pavlova-9 [17]

Answer:

$\large\boxed{x\dfrac{17}{7}}\\\downarrow\\\boxed{x\in\left(-\infty,\ -\dfrac{117}{7}\right)\ \cup\ \left(\dfrac{17}{7};\ \infty\right)}$

Step-by-step explanation:

$|0.7x+5|>6.7\iff0.7x+5>6.7\ or\ 0.7x+56.7\qquad\text{subtract 5 from both sides}\\0.7x>1.7\qquad\text{divide both sides by 0.7}\\x>\dfrac{1.7}{0.7}\to x>\dfrac{17}{7}\\\\(2)\\0.7x+5$