Ask question

Ask question

All categories

4 years ago

8

I may sound dumb... But what is the Prime Factorization of 68?? Please if I get this right I get 20 pts!!!

2 answers:

Illusion [34]4 years ago

7 0

68
2 * 34
2 * 2 * 17 or 2^2 * 17 <===

Misha Larkins [42]4 years ago

3 0

68 is a composite number. 68 = 1 x 68, 2 x 34, or 4 x 17. Factors of 68: 1, 2, 4, 17, 34, 68. Prime factorization: 68 = 2 x 2 x 17, which can also be written<span> 2² x 17.</span>

You might be interested in

The nile river, the longest river in the world, is 66.7x100 kilometers long. What is the nile's length?

kvasek [131]

Well if you multiply 66.7 x 100 you get 6,670.0. When multiplying by numbers like 10, 100, 1,000, etc, just simply transfer the 0's. So in this case, there are 2 0's in 100, so you add 2 of the 0's behind 66.7. So when you add the 2 of the 0's you get 6,670.0 which should be your answer.

4 0

4 years ago

What is the LCM of 95 and 14

kicyunya [14]

Answer:

LCM of 95 and 14 is 1330

Step-by-step explanation:

refer to the picture for explanation

3 0

3 years ago

Sin^2(alpha) + cos^2(alpha)=? Fast plz sir is asking me rn lol

Crazy boy [7]

Answer:

the answer is 1

hope it helps

4 0

3 years ago

Is 5x + 12 = 5x + 22 a infinite real solution

Alexus [3.1K]

Answer:

No Solution

Step-by-step explanation:

There is no number that can replace x to make the equation true.

5 0

3 years ago

Read 2 more answers

Using the given information, give the vertex form equation of each parabola.

Amanda [17]

Answer:

The equation of parabola is given by : $(x-4) = \frac{-1}{3}(y+3)^{2}$

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:( $\frac{47}{12}$ ,-3)

The general equation of parabola is given by.

$(x-h)^{2} = 4p(y-k)$ , When x-componet of focus and Vertex is same

$(x-h) = 4p(y-k)^{2}$ , When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

For value of p:

p= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

p= $\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}$

p= $\sqrt{(\frac{1}{12})^{2}}$

p= $\frac{1}{12}$ and p= $\frac{-1}{12}$

Since, Focus is left side of the vertex,

p= $\frac{-1}{12}$ is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p= $\frac{-1}{12}$

$(x-h) = 4p(y-k)^{2}$

$(x-4) = 4(\frac{-1}{12})(y+3)^{2}$

$(x-4) = \frac{-1}{3}(y+3)^{2}$

8 0

3 years ago