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Mamont248 [21]
3 years ago
12

by about how much will f(x,y,z) = In root x^2 +y^2 +z^2 change if the point P(x, y, z) moves from P0(2,2,6) a distance of ds = .

1 units in the direction of 3i+6j-2k?
Mathematics
1 answer:
konstantin123 [22]3 years ago
6 0

Answer:

\frac{1}{44} \approx0.0227\hspace{3}units

Step-by-step explanation:

In order to find the answer we need to calculate the directional derivative:

D_uf(x,y,z)=\nabla f\bullet u

\nabla f =The\hspace{3}gradient\hspace{3}of\hspace{3}f\\u=Unit\hspace{3}vector

The gradient of f is:

\nabla f(x,y,z)=\langle\frac{x}{x^2+y^2+z^2}, \frac{y}{x^2+y^2+z^2},\frac{z}{x^2+y^2+z^2}\rangle

The unit vector can be found as:

u=\frac{v}{|v|} =\frac{3i+6j-2k}{\sqrt{3^2+6^2+(-2^2)} } =\langle\frac{3}{7} ,\frac{6}{7}, \frac{-2}{7} \rangle

The directional derivative at the point is:

D_uf(2,2,6)=\langle\frac{1}{22}, \frac{1}{22} ,\frac{3}{22} \rangle \bullet \langle \frac{3}{7} ,\frac{6}{7} ,\frac{-2}{7} \rangle =\frac{5}{22} \bullet \langle \frac{3}{7} ,\frac{6}{7} ,\frac{-2}{7} \rangle =\frac{5}{22}

Finally, the problem tell us that the point moves a distance of 0.1 units. Hence f(x,y,z) will move:

\frac{5}{22} * 0.1=\frac{1}{44}\approx 0.0227\hspace{3}units

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7 0
3 years ago
Which of the following expressions is equivalent to -9?
FromTheMoon [43]

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3 years ago
PLEASE HELP!!!
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Answer:

D.

Step-by-step explanation:

Find the average rate of change of each given function over the interval [-2, 2]]:

✔️ Average rate of change of m(x) over [-2, 2]:

Average rate of change = \frac{m(b) - m(a)}{b - a}

Where,

a = -2, m(a) = -12

b = 2, m(b) = 4

Plug in the values into the equation

Average rate of change = \frac{4 - (-12)}{2 - (-2)}

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Average rate of change = 4

✔️ Average rate of change of n(x) over [-2, 2]:

Average rate of change = \frac{n(b) - n(a)}{b - a}

Where,

a = -2, n(a) = -6

b = 2, n(b) = 6

Plug in the values into the equation

Average rate of change = \frac{6 - (-6)}{2 - (-2)}

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Average rate of change = 3

✔️ Average rate of change of q(x) over [-2, 2]:

Average rate of change = \frac{q(b) - q(a)}{b - a}

Where,

a = -2, q(a) = -4

b = 2, q(b) = -12

Plug in the values into the equation

Average rate of change = \frac{-12 - (-4)}{2 - (-2)}

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✔️ Average rate of change of p(x) over [-2, 2]:

Average rate of change = \frac{p(b) - p(a)}{b - a}

Where,

a = -2, p(a) = 12

b = 2, p(b) = -4

Plug in the values into the equation

Average rate of change = \frac{-4 - 12}{2 - (-2)}

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Average rate of change = -4

The answer is D. Only p(x) has an average rate of change of -4 over [-2, 2]

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Step-by-step explanation:

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However, the inverse of a parabola (like ƒ(x) = x²) is not a function, because a horizontal line intersects with the graph at two points.

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