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neonofarm [45]
3 years ago
9

Give the equation of the circle centered at the origin and passing through the point (0,5)

Mathematics
1 answer:
Julli [10]3 years ago
5 0

Answer:

x^{2} +y^{2}=25

Step-by-step explanation

The standard equation of a circle centered at origin is  x^{2} +y^{2} =r^{2}

r = radius of the circle

The circle is passing through the point (0,5)

∴ radius  r=\sqrt{(0-0)^{2}+(5-0)^{2} }

               r=\sqrt{0+25}

               r=\sqrt{25}

               r^{2}=25

∴ The equation of the circle is

     x^{2} +y^{2} = 25

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25 pages -> 30 min

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240/60= 4

Thus, the answer is 4 hours

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Mrs. Smith is making cookies. Her recipe calls for 6/8 cup of white sugar and 2/4 cup of brown sugar. How much sugar will Mrs. S
wariber [46]

Answer:

10/8 or 1 and 2/8

Step-by-step explanation:

You can convert 2/4 into 4/8 then all you have to do from there is just add to get 10/8.

Hope I could help! :)

8 0
3 years ago
I don't understand all three. What am I supposed to do and what is the answer?
AlladinOne [14]

Answer:

Step-by-step explanation:

The Domain means all possible values that x can be.

The range is the outcomes you get when you plug in the domain.

For each function, choose values for x.

Then solve

The outcome you get is f(x)

F(X) is an easier way of saying y,

If its easier this way, in terms of y, the equations would be y=-4x, y=x+6, and y=3x+2. You would solve these as you solve linear equations!

Ordered pair of [x,f(x)]

Lets Start!

#1

x | -4x | f(x)  

Lets use the values -2, -1, 0, 1, and 2 for x.

-2 | -4(-2) | 8  (-2,8)

-1 | -4(-1) | 4  (-1,4)

0 | -4(0) | 0  (0,0)

1 | -4(1) | -4  (1,-4)

2 | -4(2) | -8  (2,-8)

Domain we have right now- {-2,-1,0,1,2}

Range we have right now- {8,4,0,-4,-8}

Domain and Range of entire function- All real numbers

#2

x | x+6 | f(x)

Lets use the values -2, -1, 0, 1, and 2 for x.

-2 | -2 + 6 | 4

-1 | -1 + 6 | 5

0 | 0 + 6 | 6

1 | 1 + 6 | 7

2 | 2 + 6 | 8

Domain we have right now- {-2,-1,0,1,2}

Range we have right now- {4,5,6,7,8}

Domain and Range of entire function- All real numbers

#3

x | 3x + 2 | f(x)

-2 | 3(-2) + 2 | 4

-1 | 3(-1) + 2 | -1

0 | 3(0) + 2 | 2

1 | 3(1) + 2 | 5

2 | 3(2) + 2 | 8

Domain we have right now- {-2,-1,0,1,2}

Range we have right now- {4,-1,2,5,8}

Domain and Range of entire function- All real numbers

Hope i helped, Brainliest would be appreciated.

Have a nice day!

   -Aadi x

3 0
3 years ago
Need ASAP!!!!!!!!!!!!!!!!
Semmy [17]

Answer:

d

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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