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Naddik [55]
2 years ago
14

Tom and Susan park at different lots. To see which lot is busier, they count the numbers of cars in the lots each day as they ar

rive. Their data are shown in the box plots. Image of a number line with box plot for Tom's data and a box plot for Susan's data Answer the questions to compare the variability of the data sets. 1. What is the interquartile range for Tom's data? Explain how you found the interquartile range. Write your answer in the space below. 2. What is the interquartile range for Susan's data? Write your answer in the space below. 3. Whose data are more variable? Write your answer in the space below.
Mathematics
1 answer:
user100 [1]2 years ago
7 0

Answer:

Please see my Work, Attached.

Step-by-step explanation:

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If \triangle △RST is isosceles. find x then find m∠S.
rusak2 [61]

Answer:

s=32

Step-by-step explanation:

15x-31 = 9x+11

6x=42

x=7

2(63+11)= 2(74)= 148

180-148=32

3 0
3 years ago
Read 2 more answers
Jake has two similar cylindrical pipes. The radius of the first cylindrical pipe is 5 cm. The circumference of the second cylind
Anna11 [10]
V=hpir^2
c=2pir

assuming they havve same height

first one is
v=hpi5^2
v=25hpi

2nd one
c=2pir=20pi
2pir=20pi
2r=20
r=10
v=hpir^2
v=hpi10^2
v=100hpi

big/small=100hpi/25hpir=4

4 times greater
4 0
3 years ago
Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete
icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 17 means that N = 17

4 are carrying nucleas weapons, which means that k = 4

9 are destroyed, which means that n = 9

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X > 1) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294

P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0
3 years ago
X-(-4) = 10<br> X=<br> Answer here
Alinara [238K]

Answer: x = 6

Step-by-step explanation:

X - (-4) = 10

X + 4 = 10

X = 10 - 4 = 6

8 0
3 years ago
Read 2 more answers
Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
krok68 [10]

Answer:

Mean = 51.4.

Mode = 49.

Median = 52.

Range = 6.

Step-by-step explanation:

Mean = Sum of all observations / Number of observations.

Mean = (49+49+54+55+52+49+52)/7

Mean = 360/7

Mean = 51.4 (to the nearest tenth).

Mode = The most repeated values = 49 (repeated 3 times).

Range = Largest Value - Smallest Value = 55 - 49 = 6.

Median = The central value of the data.

First, arrange the data in the ascending order: 49, 49, 49, 52, 54, 55, 55.

It can be seen that the middle value is 52. Therefore, median = 52!!!

7 0
3 years ago
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