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Zina [86]
3 years ago
12

Compré 5 distintos tipos de semillas de flores para sembrarlas en el jardin una tras de otra.

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0

Responder:

120 maneras.

Explicacion paso a paso:

Cinco tipos diferentes de semillas.

El numero de formas de organizar, n, a diferencia de los objetos en una linea es n!

Entonces, para sembrar 5 tipos diferentes de flores, serian 5!

5! = 5 * 4 * 3 * 2 * 1 = 120 vias.

Por lo tanto, hay 120 formas de sembrar las cinco semillas.

Hablo ingles y escribo ingles. Espero que entiendas. Acabo de utilizar el traductor de Google para intentar que la respuesta sea mas clara para ti :).

Por favor, califique con 5 estrellas, gracias, y deme lo mejor (Brainliest). Gracias.

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7+8=x/3<br> how do i solve this
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Because this is addition, you must reverse the process by (maybe) doing x/3 and 8/1 or 7/1. Cross multiply the numerators and denominators.

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Need help as soon as possible please
Leokris [45]

Answer:

C - 10

Step-by-step explanation:

n is the number of the term

an = -2n+8

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5 0
3 years ago
A college student takes the same number of credits each semester. They had 5 credits when they started, and after 2 semesters, t
gogolik [260]

The rate at which the college student earns credit is 13 credits per semester.

<h3>What is an equation?</h3>

An equation is the statement that illustrates the variables given. In this case, two or more components are taken into consideration to describe the scenario.

Let the credit earned each semester be x.

This will be illustrated as:

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Divide

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5 0
1 year ago
1,792 divided by 3.5
sladkih [1.3K]

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H(t)=t² + 4t + 3
Alina [70]

Answer:

1) The zeros of the function is at t=-3,-1.

2) The vertex of the parabola is (-2,-1).

Step-by-step explanation:

Given : Function h(t)=t^2+4t+3

To find :

1) What are the zeros of the function?

2) What is the vertex of the parabola?

Solution :

1) The zeros of the function,

To find the roots of the equation, replace  h(t)=0 and solve.

t^2+4t+3=0

Applying middle term split,

t^2+3t+t+3=0

t(t+3)+1(t+3)=0

(t+3)(t+1)=0

t=-3,-1

The zeros of the function is at t=-3,-1.

2) The vertex of the parabola,

Comparing ax^2+bx+c with t^2+4t+3

Here, a=1, b=4, c=3

The x -coordinate of the vertex is given by -\frac{b}{2a}

-\frac{b}{2a}=-\frac{4}{2(1)}=-2

For y-coordinate put t=-2 in the function,

h(-2)=(-2)^2+4(-2)+3

h(-2)=4-8+3

h(-2)=-1

The vertex of the parabola is (-2,-1).

5 0
2 years ago
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