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Aliun [14]
3 years ago
11

PLEASE HELP!!! Evaluate the expression when b=4 and y= -3-b+2y

Mathematics
2 answers:
oee [108]3 years ago
7 0

Answer: -10

Step-by-step explanation: All you have to do is plug the values into the equation. -4+2(-3). Then you solve the equation using PEDMAS.

1. -4+2(-3)

2. -4+(-6)

3.-4-6

4.-10

Anarel [89]3 years ago
4 0

Answer:

8

Step-by-step explanation:

-b + 2y

if

b = 4

and

y = 3

then:

-b + 2y = -4 + 2*6 = -4 + 12

= 8

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Max because 360/24 is 15 and Holly doesn't say how they would put the oranges in each bag. The bags have to have an equal amount of oranges for each bag to be worth $1.50.
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4 years ago
Find the product of 2x2 + 3x - 6 and 4x3 - x + 7.​
yanalaym [24]

Answer:

8x^5 + 12x^4 - 26^3 + 11x^2 + 27x - 42

Step-by-step explanation:

(2x^2 + 3x - 6)(4x^3 - x + 7)

8x^5 -2x^3 +14x^2 + 12x^4 - 3x^2 + 21x -24x^3 + 6x - 42

8x^5 + 12x^4 - 26^3 + 11x^2 + 27x - 42

5 0
3 years ago
2x - 3y = 14<br> 5x - 3y = -10
pshichka [43]

Answer:

x = -8

y = -10

Step-by-step explanation:

Elimination

2x - 3y = 14

5x - 3y = -10

__________--

-3x = 24

x = 24/-3

x = -8

Subsitution

2x - 3y = 14

2(-8) - 3y = 14

-16 - 3y = 14

-3y = 14 + 16

-3y = 30

y = 30/-3

y = -10

5 0
3 years ago
Hello, I need Help Please What is the Descending Order 219746, 612191, 194937
jolli1 [7]

Answer:

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Step-by-step explanation:

this is the answer

7 0
3 years ago
1.08t can be written as (1.081/12)12t to give the approximate equivalent monthly interest rate based on an annual rate of 8%. Us
kobusy [5.1K]
<span>Because <span>t <span>is given in years and 1.08 <span>= <span>1 <span>+ <span>0.08, the annual percent increase
<span>is 8%.
To find the monthly percent increase that gives an 8% annual increase,
<span>use the fact that
t = \frac{1}{12} * 12 t<span><span><span><span>
<span><span><span><span>and the properties of exponents to rewrite the
model in a form that reveals the monthly growth rate.</span></span></span>
</span></span></span></span></span></span></span></span></span></span></span></span></span></span>
1.08^{t} &#10;= 1.08^{(1/12)(12t)} &#10;= (1.08^{1/12}) ^{12t} &#10;=  1.0064634^{12t}
6 0
3 years ago
Read 2 more answers
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