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jonny [76]
2 years ago
12

What is the equivalent to five and two tenths

Mathematics
2 answers:
Phoenix [80]2 years ago
8 0

Answer:

5 2/10 or 520%

Step-by-step explanation:

Wittaler [7]2 years ago
5 0
The answer to your question is: 5 2/10 or 520%
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What is 2,200x in scientific notation?
strojnjashka [21]
Answer: 2.2x * 10^3
You would have to move the decimal place 3 times for 2.2x to get 2,200x, thus you get 10^3.

Hope this helps!

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3 years ago
Lola bought 4.25 yards of ribbon. The ribbon cost $1.59 per yard. What was the
iren2701 [21]
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2 years ago
PLEASE HELP ME ASAP SOMEONE
Eduardwww [97]

Answer:

E (3,-1)   D (-2, -2)   G (-1, 3)    F (3, 2)

Step-by-step explanation:

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2 years ago
A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measurin
Ratling [72]

Answer:

The standard deviation of weight for this species of cockroaches is 4.62.

Step-by-step explanation:

Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

To find : What is the approximate standard deviation of weight for this species of cockroaches?

Solution :

We have given,

Mean \mu=50

The sample mean x=55

A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

i.e. P(X>55)=14%=0.14

The total probability needs to sum up to 1,

P(X\leq 55)=1-P(X>55)

P(X\leq 55)=1-0.14

P(X\leq 55)=0.86

The z-score value of 0.86 using z-score table is z=1.08.

Applying z-score formula,

z=\frac{x-\mu}{\sigma}

Where, \sigma is standard deviation

Substitute the values,

z=\frac{x-\mu}{\sigma}

1.08=\frac{55-50}{\sigma}

1.08=\frac{5}{\sigma}

\sigma=\frac{5}{1.08}

\sigma=4.62

The standard deviation of weight for this species of cockroaches is 4.62.

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3 years ago
There is a number line below and an equation. How do you solve the equation and then put it on the number line?
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