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Paha777 [63]
3 years ago
14

The points R(-4,3), S(1, -3), and T(2, 1) are connected to form ARST.

Mathematics
1 answer:
LenKa [72]3 years ago
6 0

Answer:

Scalene

Step-by-step explanation:

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Answer: if 28 is 6 meters, 14 is 3 meters. 14 times 3 is 42

Step-by-step explanation: WAIT I WAS THINKING WRONG DONT LISTEN TO ME!

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Hai are yall real:/?
sammy [17]

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yes surprisingly

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3 years ago
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What can you triple and then subtract by 7 to get -1
iVinArrow [24]

Answer:

2

Step-by-step explanation:

<em>let </em><em>the </em><em>number </em><em>be </em><em>x</em>

<em>The</em><em>n</em><em> </em><em>you </em><em>triple </em><em>the </em><em>x </em><em>and </em><em>minus </em><em>7 </em><em> </em><em>from </em><em>it </em><em>and </em><em>you </em><em>equate </em><em>it </em><em>to </em><em>-</em><em>1</em>

7 0
3 years ago
PLZ dont ignore me! I need help on this :(
uysha [10]
Answer: It’s the second one!

Explanation: The dot is open and pointing to the side of the numbers greater than -3. It has to be an open dot because it is “greater than -3” not “greater than or equal to-3”! :)
4 0
3 years ago
Pleasee help ASAP!! No links pleaseee!!!
Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(2-0)^2+(4-1)^2}

AB=\sqrt{(2)^2+(3)^2}

AB=\sqrt{4+9}

AB=\sqrt{13}

Similarly,

BC=\sqrt{(6-2)^2+(0-4)^2}

BC=\sqrt{(4)^2+(-4)^2}

BC=\sqrt{16+16}

BC=\sqrt{32}

BC=4\sqrt{2}

Now, the length of the rectangle is AB=\sqrt{13} and the width of the rectangle is BC=4\sqrt{2}. So, the area of the rectangle is:

A=length \times width

A=\sqrt{13}\times 4\sqrt{2}

A=4\sqrt{26}

A\approx 20

Therefore, the area of the rectangle is 20 square units.

3 0
3 years ago
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