Answer:
Case(a): ![p[b]=\frac{1}{3}p[a]](https://tex.z-dn.net/?f=p%5Bb%5D%3D%5Cfrac%7B1%7D%7B3%7Dp%5Ba%5D)
Case(b): ![p[b]=0](https://tex.z-dn.net/?f=p%5Bb%5D%3D0)
Case(c): ![p[b]=\frac{1}{2}p[a\cap b]](https://tex.z-dn.net/?f=p%5Bb%5D%3D%5Cfrac%7B1%7D%7B2%7Dp%5Ba%5Ccap%20b%5D)
Step-by-step explanation:
Given
(a) events a and b are a partition and p[a] = 3p[b].
(b) for events a and b, p[a ∪ b] = p[a] and p[a ∩ b] = 0.
(c) for events a and b, p[a ∪ b] = p[a]− p[b].
we have to find the p[b] in each case:
Case (a): events a and b are a partition and p[a] = 3p[b].
gives
Case (b): for events a and b, p[a ∪ b] = p[a] and p[a ∩ b] = 0.
![p[a\cup b]=p[a]](https://tex.z-dn.net/?f=p%5Ba%5Ccup%20b%5D%3Dp%5Ba%5D)
⇒![p[a]+p[b]-p[a\cap b]=p(a)](https://tex.z-dn.net/?f=p%5Ba%5D%2Bp%5Bb%5D-p%5Ba%5Ccap%20b%5D%3Dp%28a%29)
⇒ ∵ p[a ∩ b] = 0.
Case(3): for events a and b, p[a ∪ b] = p[a]− p[b].
p[a ∪ b] = p[a]− p[b]
⇒ ![p[a]+p[b]-p[a\cap b]=p[a]-p[b]](https://tex.z-dn.net/?f=p%5Ba%5D%2Bp%5Bb%5D-p%5Ba%5Ccap%20b%5D%3Dp%5Ba%5D-p%5Bb%5D)
⇒ ![2p[b]=p[a\cap b]](https://tex.z-dn.net/?f=2p%5Bb%5D%3Dp%5Ba%5Ccap%20b%5D)
⇒
Surface area of a sphere=4pi(r^2)
Volume of a sphere=(4/3)pi(r^3)
You need to find the r value to calculate surface area, so I'll solve for that first.
(4/3)pi(r^3)=2254pi
(4/3)(r^3)=2254
r^3=1690.5
r=(1690.5)^(1/3), around 11.9126m
Substitute this in to find surface area
A=4pi(r^2)=4pi(11.9126)^2
=1783.2818 m^2
Answer:
12
Step-by-step explanation:
Answer:):Step-by-step explanation:
sagutan ko sana kaso mahirap
First, change the given equation to slope-intercept form:
4y = 3x + 4
y = (3/4)x + 1
Because the line we are trying to write the equation for is parallel to the above line, the new line must have the same slope (3/4).
We can then substitute (4, 0) to find the y-intercept (b):
0 = (3/4) * 4 + b
0 = 3 + b
-3 = b
Our y-intercept is -3
We can now write the whole equation:
y = (3/4)x - 3
Your final answer is y = (3/4)x - 3
Hope this helps!! Let me know if you have ANY questions.
