Atom : B
Cation : C
Anion : A
<h3>Further explanation</h3>
Given
Pictures for atom, anion, and cation
Required
Classification
Solution
Represent atom : Picture B
Number of protons = number of electrons = 6 = neutral atom
Represent cation : Picture C
Number of protons > number of electrons = 6>5 : charge +1(positive charge)
Represent anionn : Picture A
Number of protons < number of electrons = 5<6 : charge -19negative charge)
Answer:
THE MOLARITY IS 2.22 MOL/DM3
Explanation:
The solution formed was as a result of dissolving 37.5 g of Na2S in 217 g of water
Relative molecular mass of Na2S = ( 23* 2 + 32) = 78 g/mol
Molarity in g/dm3 is the amount of the substance dissolved in 1000 g or 1 L of the solvent. So we have;
37.5 g of Na2S = 217 g of water
( 37.5 * 1000 / 217 ) g = 1000 g of water
So, 172.81 g/dm3 of the solution
So therefore, molarity in mol/dm3 = mol in g/dm3 / molar mass
Molarity = 172.81 g/dm3 / 78 g/mol
Molarity = 2.22 mol/dm3
The molarity of the solution is 2.22 mol/dm3
A <span>It increased the number of molecular collisions.
Hope this helps</span>
Answer:
A substance that has a fixed chemical composition throughout is called a pure substance such as water, air, and nitrogen. A pure substance does not have to be of a single element or compound.
Explanation:
Compound: A substance that contains more than one element
pure substance: is made up of one substance made up of only one type of molecule
Answer:
The balanced chemical reaction of combustion of methane is:
734 liters of carbon dioxide gas is produced. .
Explanation:
The balanced chemical reaction of combustion of methane is:
Mass of methane gas = 0.500 kg = 500 g (1 kg= 1000 g)
Moles of methane = 
According to reaction, 1 mole of methane gas gives 1 mole of carbon dioxide gas. Then 31.25 moles of methane will give :
of carbon dioxide
Using ideal gas equation:
PV = nRT
where,
P = Pressure of gas = 
V = Volume of gas =?
n = number of moles of carbon dioxide gas = 31.25 mol
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas =13.0°C=13.0+273.15 K= 286.15 K
Putting values in above equation, we get:
V = 734.15 L ≈ 734 L
734 liters of carbon dioxide gas is produced. .
