<h2>
Answer:</h2>
7 hydrogen atoms
<h2>
Explanation:</h2>
N<em><u>H4</u></em>C2<em><u>H3</u></em>02
In this problem we see the hydrogen atom twice, along with the numbers 4 and 3 next to them. (as shown above in bold & underlined)
So, in order to find how many there are in all you add both hydrogen atoms together-
H4+H3= H7
therefore, there are 7 hydrogen atoms in all
Well because the lowest possibility of having a decen is 3-decene so 6-decene is not possible. Hope this helps!! :)
Answer:
B: Na(s) + Cl2(g) + 3O2(g) = 2NaClO3(s)
Explanation:
We are looking for enthalpy of formation, so we want to see reactance in their natural standard form.
Thus, we want to see the reactance of Na, Cl2 and O2.
The only option that has the correct form of Na, Cl2 and O2 is B.
Na(s) + Cl2(g) + 3O2(g) = 2NaClO3(s)
