All categories

3 years ago

A 1.0 mol sample of which of the following compounds has the greatest mass?

Chemistry

1 answer:

Sholpan [36]3 years ago

5 0

Answer:

D) N2O5

Explanation:

The molar mass of a substance is defined as the mass of this substance in 1 mol. To solve this question we must find the molar mass of each option:

Molar mass NO:

1N = 14g/mol*1

1O = 16g/mol*1

14+16 = 30g/mol

Molar mass NO2:

1N = 14g/mol*1

2O = 16g/mol*2

14+32 = 46g/mol

Molar mass N2O:

2N = 14g/mol*2

1O = 16g/mol*1

28+16 = 44g/mol

Molar mass N2O5:

2N = 14g/mol*2

5O = 16g/mol*5

28+80 = 108g/mol

That means the compound with the greatest mass is:

You might be interested in

Boats typically have several metal fittings where ropes can be fastened. What is the name for these metal fittings?

nadezda [96]

The name for these metal fittings is cleats.
Cleats refer to the hooks on your boat and the dock where you can fasten a boat in order to keep it from flowing away while you're not using it. A keel is located under your boat and provides stability; a transom is the part of your boat on the stern where the motor is located; a tiller is a lever you use to turn your boat.

3 0

3 years ago

Solid foods digest faster than liquids.

Alexeev081 [22]

The answer to this question would be: false

Solid foods have a smaller surface that can be digested by enzyme compared to the liquids food. Liquid food like milk can easily be digested as the substrate spread in the solution to the enzyme can bind freely to the substrate. In solid food, the area that can be digested would be only the outer part of the food. That is why organism have teeth so the food can be cut into smaller pieces, increasing the surface area that can be digested.

3 0

3 years ago

Read 2 more answers

Why does the dehydration of an alcohol more often use concentrated sulfuric acid, H 2 S O 4 HX2SOX4, as the acid catalyst rather

Dimas [21]

KAnswer:

See explanation

Explanation:

It is more common to use H2SO4 for dehydration reaction rather than HCl because HCl contains a good nucleophile,the chloride ion.

Owing to the presence of the chloride ion, a substitution reaction involving the chloride ion may also proceed also thereby affecting the elimination reaction.

Also, concentrated H2SO4 is a very good drying agent thus, as long as it is used, the alcohol substrate is completely dehydrated to yield the alkene.

Note that HCl is not a dehydrating agent.

4 0

2 years ago

A stream consisting of 48.9 mole% benzene (B) and 51.1% toluene (T) is fed at a constant rate to a process unit that produces tw

marshall27 [118]

The vapor flowrate will vary with time by ; gradually increasing from zero to one half of the molar feed flow rate and then remain constant ( C )

Although the options related to your question is missing attached below are the missing options

Vapor flow rate is the amount of vapor per unit of time that flows through a specific area at a given time .

Given that the stream consists of 48.9 mole% of benzene and 51.1% toluene fed at a constant rate into a process unit. The vapor flowrate will vary with time because it will gradually increase from zero to 1/2 of the molar feed flow rate before it will remain constant.

Hence we can conclude that The vapor flowrate will vary with time by gradually increasing from zero to one half of the molar feed flow rate and then remain constant.

Learn more : brainly.com/question/24232544

7 0

2 years ago

Predict whether or not a precipitate forms upon mixing 175.0 ml of a 0.0055 mkcl solution with 145.0 ml of a 0.0015 m agno3 solu

REY [17]

Step 1: Write down the chemical reaction

KCl(aq) + AgNO3(aq) → AgCl(s) + KNO3(aq)

The precipitate that can be expected is AgCl

Step 2: Calculate the moles of KCl and AgNO3

# moles of KCl = V(KCl) * M(KCl)

= 0.175 L * 0.0055 moles/L = 9.63*10⁻⁴ moles

# moles of AgNO3 = V(AgNO3) * M(AgNO3)

= 0.145 L * 0.0015 moles/L = 2.18*10⁻⁴ moles

Since moles of AgNO3 < KCl, the former is the limiting reagent

Therefore, moles of AgCl formed = 2.18*10⁻⁴ moles

Step 3: Predict if AgCl precipitate will be formed

The solubility product Ksp for AgCl = 1.6 *10⁻¹⁰

i.e.

AgCl(s) ↔ Ag⁺(aq) + Cl⁻(aq)

Ksp = [Ag+][Cl-]

if [Ag+][Cl-] > Ksp then precipitation will occur

Now total volume of the solution = 175 + 145 = 320 ml = 0.320 L

[Ag+] = [Cl-] = 2.18*10⁻⁴ moles/0.320 L = 6.81*10⁻⁴ M

[Ag+][Cl-] = (6.81*10⁻⁴)² = 4.64 *10⁻⁷

Since [Ag+][Cl-] > Ksp, AgCl precipitate will be formed.

8 0

3 years ago