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2 years ago

If 9 is added to a number x the result is greater than 17. Find the range of values of x

Mathematics

1 answer:

Murljashka [212]2 years ago

8 0

The solution of inequality shows that the range is x >8.

<h3>Domain and Range </h3>

The domain of a function is the set of input values for which the function is real and defined. In the other words, when you define the domain, you are indicating for which values x the function is real and defined.

While the domain is related to the values of x, the range is related to the possible values of y that the function can have.

<h3>Inequalities</h3>

Inequality is a mathematical expression that does not present equality between both sides. It is represented by symbols: <, ≤, > and ≥.

For solving this question, you should convert the text of the problem into an algebraic expression. Consequently, you will have:

x+9 > 17

x > 17-9

x > 8

Therefore, the range is x>8.

Learn more about the range here:

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An international company has 27,700 employees in one country. if this represents 33.6% of the company's employees, how many empl

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3 years ago

prove that if f is integrable on [a,b] and c is an element of [a,b], then changing the value of f at c does not change the fact

Neko [114]

Answer with Step-by-step explanation:

We are given that if f is integrable on [a,b].

c is an element which lie in the interval [a,b]

We have to prove that when we change the value of f at c then the value of f does not change on interval [a,b].

We know that limit property of an integral

$\int_{a}^{b}f dt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$

$\int_{a}^{b} fdt=f(b)-f(a)$ ....(Equation I)

Using above property of integral then we get

$\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$ ......(Equation II)

Substitute equation I and equation II are equal

Then we get

$\int_{a}^{b}fdt= f(c)-f(a)+{f(b)-f(c)}$

$\int_{a}^{b}fdt=f(c)-f(a)+f(b)-f(c)=f(b)-f(a)$

$\int_{a}^{c}fdt+\int_{c}^{b}fdt=f(b)-f(a)$

Therefore, $\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b}fdt$ .

Hence, the value of function does not change after changing the value of function at c.

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3 years ago

If the modulus is 4 and the real part is –2.0, what is the imaginary part?

faltersainse [42]

Answer:

3.5

Step-by-step explanation:

edgenuity2020

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4 years ago

Can u solve these 4 me?

Ber [7]

So for this:

(-1/3+-0.3/3+1) ^2

(-1/3-0.1+1)^2

(1-1.3/3)^2

(1-0.433333)^2

0.566667^2

Answer: 0.321111

0.32

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3 years ago