Can u solve these 4 me?

Mathematics

1 answer:

Ber [7]3 years ago

8 0

So for this:

(-1/3+-0.3/3+1) ^2

(-1/3-0.1+1)^2

(1-1.3/3)^2

(1-0.433333)^2

0.566667^2

Answer: 0.321111

0.32

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The function h(t) = –16t2 + 96t + 6 represents an object projected into the air from a cannon. The maximum height reached by the

jolli1 [7]

If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.

The derivative is      h'(t) = -32 t + 96 .

At the maximum ... h'(t) = 0

   32 t = 96 sec

   t =  3 sec .
___________________________________________

If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.

In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.

   150 ft = -16 t² + 96 t + 6

Subtract 150ft from each side: -16t² + 96t - 144 = 0 .

Before you attack that, you can divide each side by -16,
making it a lot easier to handle:

     t² - 6t + 9 = 0

I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)

The answer is from AL2006

6 0

4 years ago

Suppose that time spent on hold per call with customer service at a large telecom company is normally distributed with a mean µ

lana66690 [7]

Answer:

0.3108 is the probability that the sample mean is between 7.8 and 8.2 minutes.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8 minutes

Standard Deviation, σ = 2.5 minutes

Sample size, n = 25

We are given that the distribution of time spent is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{2.5}{\sqrt{25}} = 0.5$

P(sample mean is between 7.8 and 8.2 minutes)

$P(7.8 \leq x \leq 8.2)\\\\ = P(\displaystyle\frac{7.8 - 8}{0.5} \leq z \leq \displaystyle\frac{8.2-8}{0.5})\\\\ = P(-0.4 \leq z \leq 0.4})\\\\= P(z < 0.4) - P(z < -0.4)\\\\= 0.6554 -0.3446= 0.3108$