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QveST [7]
3 years ago
6

Can u solve these 4 me?

Mathematics
1 answer:
Ber [7]3 years ago
8 0

So for this:

(-1/3+-0.3/3+1) ^2

(-1/3-0.1+1)^2

(1-1.3/3)^2

(1-0.433333)^2

0.566667^2

Answer: 0.321111

0.32

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Solve x:12 : x = 8:6<br> plase help this means a lot to me
kondor19780726 [428]
If 6 goes to 12, if it remains proportional, it should be x2. So 8 x 2 = 16. X = 16
5 0
3 years ago
job starting salary of 81,000 and gets a 2% raise every year.what is the expected salary after the eight year ? please explain h
Neporo4naja [7]

Answer:

hell have 120,000

Step-by-step explanation:


8 0
3 years ago
What is the sign of a^72*(-3/7) when a is a negative number
Elis [28]

Answer:

Sign is positive

Step-by-step explanation:

Negative number^72=negative number

negative number *(-3/7)=posigive number

7 0
3 years ago
Is 19qt bigger than 5gal
agasfer [191]

Answer:

Step-by-step explanation:

No, there are 4 quarts in 1 gallon, so there are

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7 0
3 years ago
Let X denote the time from the present until the stock market hits 25,000. If X ≤ 1, you win $10, 000X. If X &gt; 1, you win not
const2013 [10]

Answer: $6321

Step-by-step explanation:

Expected value is given as exactly what you might think it means intuitively, the return you can expect for some type of action.

The basic expected value formula is the probability of an event multiplied by the amount of times the event happens:(P(x) * n).

he formula for the Expected Value for a binomial random variable is:

P(x) * X.

X is the number of trials and P(x) is the probability of success.

The formula for calculating the Expected Value where there are multiple probabilities is:

E(X) = ∑X * P(X)

The equation is basically the same, but here you are adding the sum of all the gains multiplied by their individual probabilities instead of just one probability.

Calculating the expected value of winning as follows:

Given,

Fx= e^-x, x is greater or equal to 0

Now, P less than or equal to zero =

[-e^-x] ^1

e^-0 - e^-1

= 1 - e^-1

= 0.6321

and P(x>1) = 1-0.6321= 0.3679

Therefore,Let y= amount of winnings.

Based on the above given information,

y= $10000 0

P(y)= 0.6321 0.3679

The expected value of winning:

E(y) = ΣyP(y)

E(y) = 10000 × 0.6321 + 0 × 0.3679

E(y) = $6321

Therefore, the expected value of winning is $6321

5 0
3 years ago
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