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3 years ago

Algebra Vocabulary Crossword help ?!

Mathematics

2 answers:

skad [1K]3 years ago

6 0

1.) Function Notation
9.) Linear Function

avanturin [10]3 years ago

5 0

1. a relation described in word format (17 letter) is <span> "is direct variation"

9. a way to name a function identifying its input (16 letter) is "</span><span>f of x equals x square"
</span>

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Need some help with the answer to the question

kicyunya [14]

Answer:

(- 4, 27 )

Step-by-step explanation:

Equate the right sides of both equations, that is

x² - 2x + 3 = - 2x + 19 ← subtract - 2x + 19 from both sides

x² - 16 = 0 ← in standard form

(x - 4)(x + 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x + 4 = 0 ⇒ x = - 4

Substitute these values into f(x) = - 2x + 19

f(4) = - 2(4) + 19 = - 8 + 19 = 11 ⇒ (4, 11 )

f(- 4) = - 2(- 4) + 19 = 8 + 19 = 27 ⇒ (- 4, 27 )

8 0

3 years ago

At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs

rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - $^9C_1=9$

Number of ways for second place - $^8C_1=8$

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - $^8C_1=8$

Number of ways for second place - $^7C_1=7$

Total number of different tickets are possible is

$n=9\times 8\times 8\times 7$

$n=4032$

Therefore, 4032 different tickets are possible.

8 0

3 years ago

The missing boxes please help

zalisa [80]

Multiply each scale factor by the first set of given perimeter and area
As shown in the picture below

6 0

1 year ago

Write a cubic function with zeros of -3, -5 and 2

Lady bird [3.3K]

For zeroes of r1,r2,r3, the factors of the function, f(x) are
(x-r1)(x-r2)(x-r3)

zeroes of -3,-5,2
(x-(-3))(x-(-5))(x-2)=
(x+3)(x+5)(x-2)

f(x)=(x+3)(x+5)(x-2)
expanded
f(x)=x³+6x²-x-30

5 0

3 years ago

2.8t+5.7t= answer plsss

Arte-miy333 [17]

Answer:7.15t

Step-by-step explanation:

You have to add 2.8t plus 5.7t together

6 0

3 years ago

Read 2 more answers