Answer:
Step-by-step explanation:
the first ine make sense to me
if not right sorry
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
Answer:
I hope this helps you and you have an amazing day the answer
Width=12
Length=30
Step-by-step explanation:
L=2W+6
is
P=2L+2W
84=2(2W+6)+2W
84=4W+12+2W
84=6W+12
6W=84-12
6W=72
W=72/6
W=12 ans. for the width.
L=2*12+6=24+6=30 ans. for the length.
Proof:
84=2*30+2*12
84=60+24
84=84
Answer: They charge the same amount.
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
$50-6 (ticket to game) = 44 - $20 (the balance she wants to have left) = $24.
$24/2=12 (amount of hotdogs she can buy)