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zvonat [6]
2 years ago
7

Genetic variation can occur amongst siblings since:PLEASE HELP ME 2 more questions

Physics
1 answer:
AfilCa [17]2 years ago
3 0

Answer:

d: each offspring inherts a unique combination of genes from both parents.

Explanation:

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A vegatable garden is 12 meters long by 7 meters wide.It is home to 168 mice.What is the population density of the mice?
chubhunter [2.5K]
Density= population/area
area= 12 X 7 = 84 m^2
density= 168/84= 2 mice per m^2
5 0
4 years ago
A stunt woman of mass m falls into a net during the filming of an action movie. Assume she experiences upward acceleration magni
Rashid [163]

Answer:

M= F^n / a+g

Explanation:

This shows correctly Newton’s second law, where sum of forces is divided by mass is equal to acceleration. Also mass can’t be negative so F^n is positive.

8 0
3 years ago
Read 2 more answers
A ball weighing 1 lb is attached to a string 2 feet long and is whirled in a vertical circle at a constant speed of 10 ft/sec.
fredd [130]

Explanation:

It is given that,

Mass of the ball, m = 1 lb

Length of the string, l = r = 2 ft

Speed of motion, v = 10 ft/s

(a) The net tension in the string when the ball is at the top of the circle is given by :

F=\dfrac{mv^2}{r}-mg

F=m(\dfrac{v^2}{r}-g)

F=1\ lb\times (\dfrac{(10\ ft/s)^2}{2}-1\ lb\times 32\ ft/s^2)

F = 18 N

(b) The net tension in the string when the ball is at the bottom of the circle is given by :

F=\dfrac{mv^2}{r}+mg

F=m(\dfrac{v^2}{r}+g)

F=1\ lb\times (\dfrac{(10\ ft/s)^2}{2}+1\ lb\times 32\ ft/s^2)

F = 82 N

(c) Let h is the height where the ball at certain time from the top. So,

T=mg(\dfrac{r-h}{r})+\dfrac{mv^2}{r}

T=\dfrac{m}{r}(g(r-h)+v^2)

Since, v^2=u^2-2gh

T=\dfrac{m}{r}(u^2-3gh+gr)

Hence, this is the required solution.

6 0
3 years ago
I NEED HELP ASAP! BRAINIEST TO THE CORRECT ANSWER. HELP ME NOW!
sergij07 [2.7K]

Answer:

<h3>a)</h3>

\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}

  • V = 12 V
  • P = 24 W

\implies \mathsf{24=\frac{12^2}{R} }

\implies \mathsf{24R=12^2 }

\implies \mathsf{24R=144 }

<u>=> R= 6 Ohms(Ω)</u>

<h3>b)</h3>

\boxed{\mathfrak{Power(P)=\frac{Voltage(V)^2}{Resistance(R)} }}

  • Power (P)= 100 W

<em>these lights operate at the usual 240 volts direct from the main electricity supply. Therefore,</em>

  • V = 240 V

\implies \mathsf{100=\frac{240^2}{R} }

<em>R and 100 can interchange places</em>

\implies \mathsf{R=\frac{240^2}{100} }

\implies \mathsf{R=\frac{57600}{100} }

<u>=> R = 576 Ω</u>

<u></u>

By Ohm's Law:

\boxed{\mathsf{Voltage(V)=Current(I) \times Resistance(R)}}

=> 240 = I × 576

=>

=> I = 0.417 A

<h3 /><h3>c)</h3>

I don't know it's resistance,... so sorry

<h3>d)</h3>

The brightness of the bulb in series is <em><u>less than</u></em> when they're placed individually.

For bulbs in series their resistance gets added to form the equivalent resistance of the two bulbs.

Their resistances are nothing but mere numbers and the sum of two numbers(positive of course) is greater than the numbers.

So, the effective resistance of some bulbs in series <u>is more</u> than the individual resistance.

And

<em>Brightness, i. e., Power</em>

\boxed{\mathfrak{Power \propto  \frac{1}{Resistance} }}

If resistance increases, Power decreases.

Here, the effective resistance was for sure larger, therefore resistance was increasing, hence power decreased taking brightness along with it.

3 0
3 years ago
Is Aluminium a metalliod?
svlad2 [7]
Aluminium is ordinarily classified as a metal. It is lustrous, malleable and ductile, and has high electrical and thermal conductivity. Like most metals, it has a close-packed crystalline structure<span> and forms a cation in aqueous solution.</span>
4 0
3 years ago
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