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2 years ago

14

Jack observed his coworker Jane crying when she was called into the boss's office. Jack thinks that crying at work is a sign of

weakness that makes women unfit for employment in his industry. Jack is displaying _____.

2 answers:

ivann1987 [24]2 years ago

4 0

Jack could be displaying sexism

spin [16.1K]2 years ago

3 0

... prejudice based on misogyny.

Also a good bit of stupidity.

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Please help me , thank you

mash [69]

Answer:

Since the reading wasn't specified, it would be most likely A

Explanation:

A is the most similar to a protoplanetary disk, so it'd be A most likely

5 0

3 years ago

A simple and common technique for accelerating electrons is shown in the figure, where there is a uniform electric field between

Sunny_sXe [5.5K]

Answer : $4.483\times 10^{15}\ m/s^2$ .

Explanation:

It is given that,

Electric field strength, $E=2.55\times 10^{4}\ N/C$

We know that,

Charge of electron, $q=1.6\times 10^{-19}\ C$

Mass of electron, $m=9.1\times 10^{-31}\ kg$

From the definition of electric field, $F=qE$ ...............(1)

According to Newton's second law, F = ma..........(2)

From equation (1) and (2)

$ma=qE$

$a=\dfrac{qE}{m}$

$a=\dfrac{1.6\times 10^{-19}\ C\times 2.55\times 10^{4}\ N/C }{9.1\times 10^{-31}\ kg}$

$a=0.4483\times 10^{16}\ m/s^2$

or

$a=4.483\times 10^{15}\ m/s^2$

So, the horizontal component of acceleration of an electron is $4.483\times 10^{15}\ m/s^2$ .

Hence, it is the required solution.

7 0

3 years ago

the modulus of the vector product of two vector is 0.577 times their scalar product the angle between vectors

BaLLatris [955]

What exactly do u want me to do for u mam/sir

6 0

3 years ago

What is the force on a 1,000-kilogram elevator that is falling under the acceleration of gravity?

rjkz [21]

Answer is in this file

4 0

3 years ago

Read 2 more answers

For a science project, you would like to horizontally suspend an 8.5 by 11 inch sheet of black paper in a vertical beam of light

liubo4ka [24]

Answer:

I = 3.9 x 10⁷ W/m²

Explanation:

given,

Sheet of black paper dimension = 8.5 x 11 inch

Area of sheet = 8.5 x 11 = 93.5 inch^2

1 inch =0.0254 m

Area = 0.06032 m²

mass of sheet = 0.80 g

Force = m g = 0.8 x 9.8 x 10⁻³ N

= 7.84 x 10⁻³ N

speed of light = c = 3 x 10⁸ m/s

Using equation

$F = \dfrac{IA}{c}$

where I is the intensity of light

$7.84 \times 10^{-3} = \dfrac{I\times 0.06032}{3 \times 10^8}$

$2.352 \times 10^{6} = I\times 0.06032$

$I = \dfrac{2.352 \times 10^{6}}{0.06032}$

I = 3.9 x 10⁷ W/m²

Intensity of the light is equal to I = 3.9 x 10⁷ W/m²

4 0

3 years ago