1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stealth61 [152]
3 years ago
9

The function​ s(t) represents the position of an object at time t moving along a line. Suppose s( 1 )=123 and s( 3 )=173. Find t

he average velocity of the object over the interval of time [1,3]?
Physics
1 answer:
Wittaler [7]3 years ago
3 0

Answer:

The average velocity is v_{average}=25.

Explanation:

The average velocity is calculated in the following way:

If s(t) represents the position of an object at time t,

and s(t_{1})=a ; s(t_{2})=b, the average velocity is defined in that interval as:

v_{average}= \frac{final.position-initial.position}{elapsed.time}=\frac{b-a}{t_{2}-t_{1}}

Taking the data from the question:

v_{average}=\frac{173-123}{3-1}=\frac{50}{2}=25.

You might be interested in
Robin Hood wishes to split an arrow already in the bull's-eye of a target 40 m away.
tamaranim1 [39]

Answer:

5.843 m

Explanation:

suppose that the arrow leave the bow with a horizontal speed , towards he bull's eye.

lets consider that horizontal motion

distance = speed * time

time = 40/ 37 = 1.081 s

arrow doesnot have a initial vertical velocity component. but it has a vertical motion due to gravity , which may cause a miss of the target.

applying motion equation

(assume g = 10 m/s²)

s=ut+\frac{1}{2}*gt^{2}  \\= 0+\frac{1}{2}*10*1.081^{2}\\= 5.843 m

Arrow misses the target by 5.843m ig the arrow us split horizontally

4 0
3 years ago
PLEASE HELP THIS IS DUE TODAY!! (GIVING BRAINLIEST TO WHOEVERY ANSWERS QUICKLY AND CORRECTLY!) 15 POINTS!
Jlenok [28]

As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf. ... Like low-mass stars, high-mass stars are born in nebulae and evolve and live in the Main Sequence

hydrogen shell burning - outer layers swell. Red Giant Branch - helium ash core compresses - increased hydrogen shell burning. First Dredge Up - expanding atmosphere cools star - stirs carbon, nitrogen and oxygen upward - star heats up.

5 0
3 years ago
T or F :)
balandron [24]

That's true.

And I'll go ya a better one:

If the object is moving or not moving, at a constant or changing speed, in a straight or curvy line, and the forces on it do not cancel out and add up to zero, the object will accelerate.

4 0
3 years ago
An atom of carbon has a radius of 67.0 pm and the average orbital speed of the electrons in it is about 1.3 x 10⁶ m/s.
adoni [48]

Answer :

The least possible uncertainty in an electron's velocity is, 4.32\times 10^{5}m/s

The percentage of the average speed is, 33 %

Explanation :

According to the Heisenberg's uncertainty principle,

\Delta x\times \Delta p=\frac{h}{4\pi} ...........(1)

where,

\Delta x = uncertainty in position

\Delta p = uncertainty in momentum

h = Planck's constant

And as we know that the momentum is the product of mass and velocity of an object.

p=m\times v

or,

\Delta p=m\times \Delta v      .......(2)

Equating 1 and 2, we get:

\Delta x\times m\times \Delta v=\frac{h}{4\pi}

\Delta v=\frac{h}{4\pi \Delta x\times m}

Given:

m = mass of electron = 9.11\times 10^{-31}kg

h = Planck's constant = 6.626\times 10^{-34}Js

radius of atom = 67.0pm=67.0\times 10^{-12}m     (1pm=10^{-12}m)

\Delta x = diameter of atom = 2\times 67.0\times 10^{-12}m=134.0\times 10^{-12}m

Now put all the given values in the above formula, we get:

\Delta v=\frac{6.626\times 10^{-34}Js}{4\times 3.14\times (134.0\times 10^{-12}m)\times (9.11\times 10^{-31}kg)}

\Delta v=4.32\times 10^{5}m/s

The minimum uncertainty in an electron's velocity is, 4.32\times 10^{5}m/s

Now we have to calculate the percentage of the average speed.

Percentage of average speed = \frac{\text{Uncertainty in speed}}{\text{Average speed}}\times 100

Uncertainty in speed = 4.32\times 10^{5}m/s

Average speed = 1.3\times 10^{6}m/s

Percentage of average speed = \frac{4.32\times 10^{5}m/s}{1.3\times 10^{6}m/s}\times 100

Percentage of average speed = 33.2 % ≈ 33 %

Thus, the percentage of the average speed is, 33 %

3 0
3 years ago
If a forcé has a negativa values such as -100N, that means
Lisa [10]
Its negative
:)))))))))))))
6 0
4 years ago
Other questions:
  • The specific heat of aluminum is 0.0215 cal/g°c. if a 4.55 g sample of aluminum absorbs 2.55 cal of energy, by how much will the
    12·1 answer
  • What is the potential difference across a 15 Ω resistor that has a current of 3.0 A?
    9·2 answers
  • Which of the following statement best define tides?
    9·2 answers
  • What is the potential energy of a 3 kg- ball that is on the ground?
    7·1 answer
  • What is the kinetic energy of a 1,350kg car traveling at a speed of 12m/s?
    11·1 answer
  • Explain your observation in terms of force and Newtons 3rd law
    8·1 answer
  • Why should soft porous boards be put in cinema halls?
    15·1 answer
  • What ocean depth would the volume of an aluminium sphere be reduced by 0.10%
    15·1 answer
  • A student rides a bicycle for 15 miles in 3 hours. What is the student's speed? What else would you need to know for the velocit
    10·1 answer
  • A 15 g ball at the end of 2.4 m string is swung in the horizontal circle. It revolves once every 2.09 s. What is the magnitude o
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!