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stealth61 [152]
3 years ago
9

The function​ s(t) represents the position of an object at time t moving along a line. Suppose s( 1 )=123 and s( 3 )=173. Find t

he average velocity of the object over the interval of time [1,3]?
Physics
1 answer:
Wittaler [7]3 years ago
3 0

Answer:

The average velocity is v_{average}=25.

Explanation:

The average velocity is calculated in the following way:

If s(t) represents the position of an object at time t,

and s(t_{1})=a ; s(t_{2})=b, the average velocity is defined in that interval as:

v_{average}= \frac{final.position-initial.position}{elapsed.time}=\frac{b-a}{t_{2}-t_{1}}

Taking the data from the question:

v_{average}=\frac{173-123}{3-1}=\frac{50}{2}=25.

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Digital thermometers often make use of thermistors, a type of resistor with resistance that varies with temperature more than st
Nezavi [6.7K]

Answer:

The temperature coefficient of resistivity for a linear thermistor is 1.38\times10^{-3}^{\circ}C^{-1}

Explanation:

Given that,

Initial temperature = 0.00°C

Resistance = 75.0 Ω

Final temperature = 525°C

Resistance = 275 Ω

We need to calculate the temperature coefficient of resistivity for a linear thermistor

Using formula for a linear thermistor

R=R_{0}(1+\alpha\Delta T)

R=R_{0}+R_{0}\alpha\Delta T

\alpha=\dfrac{R-R_{0}}{R_{0}\Delta T}

Put the value into the formula

\alpha=\dfrac{275-75}{275\times(525-0)}

\alpha=1.38\times10^{-3}^{\circ}C^{-1}

Hence, The temperature coefficient of resistivity for a linear thermistor is 1.38\times10^{-3}^{\circ}C^{-1}

4 0
3 years ago
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If a car is traveling 35 m/s for 200 seconds, how far will the car travel?
Nana76 [90]

Answer:

7.14285714286

Explanation:

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3 years ago
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Why is it important for a muscle to be attached to a fixed origin at one end and a moving insertion at the other? Discuss how th
vlabodo [156]
Muscles function only by contracting. This makes it necessary for one end of the muscle to be fixed and the other mobile.
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Now, had the muscle not been fixed at one end, and contracted, it would pull both our shoulder and forearm together resulting in an ineffective movement. The desired motion is to lift the forearm (proximal and distal movement) which can only be achieved if the bicep is fixed at the shoulder and allowed to move at the forearm.
6 0
3 years ago
A mass that weight stretches a spring . The system is acted on by an external force . If the mass is pushed up and then released
olchik [2.2K]

Answer:

x = A cos wt

Explanation:

To determine the position we are going to solve Newton's second law

             F = m a

           

Spring complies with Hooke's law

          F = -k x

And the acceleration of defined by

          a = d²x / dt²

         

We substitute

        - k x = m d²x / dt²

         dx² / dt² + k/m  x = 0

Let's call

           w² = k / m

The solution to this type of differential equation is

           x = A cos (wt + Ф)

Where A is the initial block displacement and the phase angle fi is determined by or some other initial condition.

In this case the body is released so that at the initial speed it is zero

From which we derive this expression

         v = dx / dt = a w sin ( wt + Ф)

         

As the System is released for t = 0 the speed is v = 0

         v = sin Ф = 0

Therefore Ф = 0

And the equation of motion is

         x = A cos wt

4 0
3 years ago
A 7.0 kg bowling ball has a moment of inertia of 2.8x10-2 kg m2, and a radius of 0.10 m. If it rolls down the lane at an angular
slega [8]

Hi there!

Angular momentum is equivalent to:

\large\boxed{L = I\omega}

L = angular momentum (kgm²/s)

I = moment of inertia (kgm²)

ω = angular velocity (rad/sec)

Plug in the given values for moment of inertia and angular speed:

L = (0.028)(40) = \boxed{1.12 kgm^2/s}

8 0
2 years ago
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