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stealth61 [152]
3 years ago
9

The function​ s(t) represents the position of an object at time t moving along a line. Suppose s( 1 )=123 and s( 3 )=173. Find t

he average velocity of the object over the interval of time [1,3]?
Physics
1 answer:
Wittaler [7]3 years ago
3 0

Answer:

The average velocity is v_{average}=25.

Explanation:

The average velocity is calculated in the following way:

If s(t) represents the position of an object at time t,

and s(t_{1})=a ; s(t_{2})=b, the average velocity is defined in that interval as:

v_{average}= \frac{final.position-initial.position}{elapsed.time}=\frac{b-a}{t_{2}-t_{1}}

Taking the data from the question:

v_{average}=\frac{173-123}{3-1}=\frac{50}{2}=25.

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speed=Frequency X Wavelength 
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3 0
3 years ago
Determine the kinetic energy of the ball immediately after it is hit. (You must provide an answer before moving to the next part
earnstyle [38]

The question is incomplete. Here is the complete question.

A baseball palyer hits a 5.1 oz baseball with an initial velocity of 140ft/sat an angle of 40° with the horizontal as shown. Determine

a) The kinetic energy of the ball immediately after it is hit

b) The kinetic energy of the ball when it reaches its maximum height

c) The maximum height above the ground reached by the ball.

Answer: a) KE = 131.64 J

              b) KE = 0

              c) h = 126 ft

Explanation: <u>Kinetic</u> <u>energy</u> is the energy an object posses due to its motion. It can be calculated as KE=\frac{1}{2}mv^{2}

a) Kinetic energy's unit is Joule. So, we have to transform ounce in kg and ft/s in m/s for the units to correspond:

m = 5.1(0.02835)

m = 0.1445 kg

v = 140 ft = 42.67 m/s

Then, kinetic energy is

KE=\frac{1}{2}(0.1445)(42.67)^{2}

KE = 131.64 J

Kinetic energy immediately after the ball is hit is 131.64 J.

b) At its maximum height, the ball has its highest potential energy. Because of the law of conservation of energy, when potential energy is maximum, kinetic energy is minimum and vice-versa. So, at the maximum height, kinetic energy is 0.

c) This type of motion is <u>projectile</u> <u>motion</u>. The maximum height on a projectile motion can be determined by

v_{y}^{2}=v_{0y}^{2}-2g\Delta y

When h is maximum, v_{y}=0

Velocity of the ball has an angle with the horizontal, so initial velocity at the y-axis is

v_{0y}=v_{0}sin(\theta)

Substituting and solving

v_{y}^{2}=v_{0}^{2}sin^{2}(\theta)-2gh

0=(42.67)^{2}sin^{2}(40)-2(9.8)h

19.6h=(42.67)^{2}(0.643)^{2}

h=\frac{(1820.73)(0.4132)}{19.6}

h = 38.4 m

Transforming into ft: h = 126 ft

The maximum height above the ground reached by hte ball is 126 feet.

6 0
3 years ago
Which factors are used to calculate the kinetic energy of an object? Check all that apply.
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belka [17]

Answer:

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2. Newton's third law of motion is<em> naturally applied to collisions between two objects</em>. In a collision between two objects, both objects experience forces that are equal in magnitude and opposite in direction.

3. Momentum is the product of a moving object's mass and velocity. When two objects collide the total momentum before the collision is equal to the total momentum after the collision

6 0
3 years ago
A small ball of charge Q and mass m has a velocity v at infinity. It collides head-on with a ball of the same charge and mass wh
Hatshy [7]

Answer:

Explanation:

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Let the minimum distance between the balls be d  on collision.

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1/2 m v² = kQ²/d

d =2 k Q² / mv²,= 18 x 10⁹ x Q²/ m v².

8 0
4 years ago
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