Answer:
The temperature coefficient of resistivity for a linear thermistor is 
Explanation:
Given that,
Initial temperature = 0.00°C
Resistance = 75.0 Ω
Final temperature = 525°C
Resistance = 275 Ω
We need to calculate the temperature coefficient of resistivity for a linear thermistor
Using formula for a linear thermistor



Put the value into the formula


Hence, The temperature coefficient of resistivity for a linear thermistor is 
Muscles function only by contracting. This makes it necessary for one end of the muscle to be fixed and the other mobile.
Take the bicep for example.
Its origin is at the shoulder and its two heads connect to the bones of the forearm, the radius and ulna.
Now, had the muscle not been fixed at one end, and contracted, it would pull both our shoulder and forearm together resulting in an ineffective movement. The desired motion is to lift the forearm (proximal and distal movement) which can only be achieved if the bicep is fixed at the shoulder and allowed to move at the forearm.
Answer:
x = A cos wt
Explanation:
To determine the position we are going to solve Newton's second law
F = m a
Spring complies with Hooke's law
F = -k x
And the acceleration of defined by
a = d²x / dt²
We substitute
- k x = m d²x / dt²
dx² / dt² + k/m x = 0
Let's call
w² = k / m
The solution to this type of differential equation is
x = A cos (wt + Ф)
Where A is the initial block displacement and the phase angle fi is determined by or some other initial condition.
In this case the body is released so that at the initial speed it is zero
From which we derive this expression
v = dx / dt = a w sin ( wt + Ф)
As the System is released for t = 0 the speed is v = 0
v = sin Ф = 0
Therefore Ф = 0
And the equation of motion is
x = A cos wt
Hi there!
Angular momentum is equivalent to:

L = angular momentum (kgm²/s)
I = moment of inertia (kgm²)
ω = angular velocity (rad/sec)
Plug in the given values for moment of inertia and angular speed:
