HELP ME I HAVE NO IDEA

What is the quotient of 1,456 and 7?

denis-greek [22]

Answer: My fellow friend, it’s 208!

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find the exact surface area of the following. The exact surface area is

Nataliya [291]

Answer:

Surface area: 4323pi

Fill the box with the value "4323", as there is a "pi" after the box.

Step-by-step explanation:

We need to find the surface area of the cone (without the base) and the surface area of the semi sphere (without the base).

The surface area of the cone, without the base, is:

S1 = pi * r * s

Where s is the slant height.

To find s, we can use the Pythagoras' theorem with the radius and the height:

s^2 = h^2 + r^2

s^2 = 56^2 + 33^2 = 4225

s = 65

So the surface area is:

S1 = pi * 33 * 65 = 2145pi

Now, to find the surface area of the semi sphere, we just need to find half of the surface area of a sphere:

S2 = (1/2) * 4 * pi * r^2

S2 = 2 * pi * 33^2 = 2178pi

Finally to find the total surface area we just need to sum both surface areas:

S = S1 + S2 = 2145pi + 2178pi = 4323pi.

As after the box to answer there is a pi, we just need to fill the box with the value "4323"

7 0

3 years ago

Sonya can walk 6 kilometers in 3 hours. If she has to walk 10 kilometers, how much time will it take her?

vekshin1

1.8 hours because 6 km is to 3 hours as 10 km is to x hours. So you multiply 3*6 and them divide it by 10

4 0

3 years ago

Please help,, I will give you 30 points!!!

jek_recluse [69]

Answer:

is the 5.2% per hour or for the whole 25 hours?

Need to know in order to solve the question

Step-by-step explanation:

8 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So $\mu = 373, \sigma = 67$

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So $n = 5, s = \frac{67}{\sqrt{5}} = 29.96$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 373}{29.96}$

$Z = 1.23$

$Z = 1.23$ has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So $\mu = 526, \sigma = 107$