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2 years ago

5x+6y+4, 3x+7z+6, and t+6h+2s+5

Mathematics

1 answer:

Gelneren [198K]2 years ago

6 0

Answer:

1st x=66y

2nd x=35z

3rd 6h+2s+t+5

Step-by-step explanation:

MArk BRAINLIEST FOR 4 MATH ALGEBRA CALCULATORS

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2 years ago

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

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Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .

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2 years ago

Midpoint of (1,3) and (4,-5)

crimeas [40]

Answer:

The rigth answer is, ( 5/2 , -1 )

Step-by-step explanation:

To find the midpoint we use the respective formula:

m = ( x1 + x2 / 2 , y1 + y2 / 2 )

We replace:

m = ( 1 + 4/2 , 3 + (- 5) / 2 )

We solve:

m = ( 5/2 , -1 )

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2 years ago

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lisov135 [29]

Answer:

0.1001

Step-by-step explanation: Your answer is 0.1001

0.91

1011

0990

0.1001

Hope this helps you!!! :)

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lisabon 2012 [21]

Answer:

I am a 4th grader I don't know

Step-by-step explanation:

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Read 2 more answers

5x+6y+4, 3x+7z+6, and t+6h+2s+5​

5x+6y+4, 3x+7z+6, and t+6h+2s+5