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1 year ago

A figure is located at (2,0), (2,-2) and (6,0)

Mathematics

1 answer:

mario62 [17]1 year ago

4 0

Uhm is this what your looking for ?

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Marcus hired a car service to drive him to the airport. The bill came to $56.80. He gave the driver a 20% tip. How much money di

ella [17]

<span>$11.36- would be the correct answer, hope this helps. merry Christmas & Happy Holidays! =)</span>

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2 years ago

Read 2 more answers

a coin is taken at random froma purse that contains one penny, 2 nickels, 4 dimes, and 3 quarters. let x be the value of the dra

algol [13]

Answer:

x = 12.6 pennies

Step-by-step explanation:

total number of coins = 1 + 2+ 4 + 3 = 10 coins

P(penny) = $\dfrac{1}{10}$

P(nickels) = $\dfrac{2}{10}$

P(dimes) = $\dfrac{4}{10}$

P(quarters) = $\dfrac{3}{10}$

hence average value of the coin

x = Penny x P(Penny) + nickel x P(nickel) + dimes x P(dimes) + quarters x P(quarters)

nickels = 5 pennies dimes = 10 ; and quarters = 25 pennies

$x = 1 \times \dfrac{1}{10} + 5\times \dfrac{2}{10} +10\times \dfrac{4}{10} + 25\times \dfrac{3}{10}$

x = 0.1 + 1 + 4 + 7.5

x = 12.6 pennies

hence, the average pennies for the first draw is equal to x = 12.6 pennies

6 0

2 years ago

Square root of 135bc^2d^3 x square root of 5b^2d

tresset_1 [31]

Square root of (675 b^3 c^2 d^4 )

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2 years ago

A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl

Andrew [12]

Answer: $\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$ or $\dfrac{228}{91885}$ .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = $^{52}C_9$

Now , the combination of 9 cards such that exactly 6 of them are face cards = $^{12}C_{6}\times^{40}C_3$

Now , the probability that the hand contains exactly 6 face cards will be :-

$\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$

$=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}$

Hence, the probability that the hand contains exactly 6 face cards. is $\dfrac{228}{91885}$ .

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2 years ago

Which algebraic expression means “four less than three times a number”?

Monica [59]

It’s 3n-4

I might be right or wrong

5 0

2 years ago