Question

A line has a gradient of 8 and passes through the point (2,3). Find the equation of the line

Answer 1

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$\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}$

        A line has a gradient of 8 and passes through (2, 3). What is the line's equation?

$\large\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}$

       With the provided information, we can write the equation of the line in point-slope form:

          $\sf{y-y_1=m(x-x_1)}$

Where

y₁ = the y-coordinate of the point

m = gradient or slope

x₁ = the x-coordinate of the point

Substitute the values:-

$\sf{y-3=8(x-2)}$

We have our equation in point-slope form.

If you need the equation in slope-intercept form, please consult the following steps.

$\sf{y-3=8(x-2)}$

Use the distributive property and multiply 8 times x and -2:-

$\sf{y-3=8x-16}$

Now, add 3 on both sides:-

$\dashrightarrow\star\bigstar\boxed{\sf{y=8x-13}}$

Good luck.

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