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3 years ago

Find the dimensions of a rectangle with a perimeter of 52cm if it’s length is 4cm more than its width

1 answer:

5 0

So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm

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3 years ago

Read 2 more answers

Determine if events A and B are mutually exclusive.

gladu [14]

Answer:

A) Not mutually exclusive

Step-by-step explanation:

Given

$P(A) = \frac{1}{4}$

$P(B) = \frac{3}{5}$

$P(A\ or\ B) = \frac{7}{10}$

Required

Determine if they are mutually exclusive or not

Mutually exclusive are defined by:

$P(A\ or\ B) = P(A) + P(B)$

So, we have:

$P(A\ or\ B) = \frac{1}{4} + \frac{3}{5}$

Take LCM

$P(A\ or\ B) = \frac{5+12}{20}$

$P(A\ or\ B) = \frac{17}{20}$

By comparing:

$P(A\ or\ B) = \frac{17}{20}$ ---- Calculated

$P(A\ or\ B) = \frac{7}{10}$ ---- Given

We can conclude that A and B are not mutually exclusive because:

$\frac{17}{20} \ne \frac{7}{10}$

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3 years ago

<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B%204x%20%2B%206" id="TexFormula1" title="2x^{2} + 4x + 6" alt="2x^{2} + 4x +

JulijaS [17]

<h2>Answer:</h2><h2>2(x^2 + 2x + 3) or $2(x^{2} + 2x + 3)$ .</h2><h2>~</h2><h3>To find the answer, simply factor 2 out of 2x^2+4x+6 to get your final answer, </h3><h3>2(x^2 + 2x + 3)</h3><h2>~</h2><h3>Thank you for taking the time to read this!</h3><h3><u>And I hope you have a good day, Loves!</u></h3><h3><em><u>Also if I'm right can you let me know, please?</u></em></h3>

<em><u>Also Also if I am right can I please have Brainliest??</u></em>

<u>You don't need to, I'm just glad I could help. ^^</u>

(If I did help-)

And don't forget to eat a full meal, and have at least one cup of water today!

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