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disa [49]
3 years ago
10

Find the dimensions of a rectangle with a perimeter of 52cm if it’s length is 4cm more than its width

Mathematics
1 answer:
Zina [86]3 years ago
5 0
So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
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Miguel compró 253 Kilos de pescado para venderlo en su negocio, si decide vender cada kilo de pescado en Bs 1.900.000. Entonces,
Sveta_85 [38]

Answer:

Miguel recaudó Bs 480.700.000 por la venta del pescado.

Step-by-step explanation:

Con la información proporcionada puedes calcular el dinero que recaudó en total por la venta del pescado multiplicando el precio de venta de cada kilo de pescado por el número de kilos que Miguel compró:

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Total vendido=480.700.000

De acuerdo a esto, la respuesta es que Miguel recaudó Bs 480.700.000 por la venta del pescado.

7 0
3 years ago
One of the legs of a right triangle measures 6 cm and its hypotenuse measures 8 cm. Find the measure of the other leg. If necess
Vika [28.1K]
Well, this is a Pythagorean theorem problem. A^2 + B^2 = C^2, where C^2 is equal to the hypotenuse. 8 squared equals 64, so c^2 = 64 cm. The other leg can be represented by A^2, which is 36 cm. 36 + ? = 64. 64 - 36 = 28, so B^2 equals 28. Now, to find the measurement of the other leg, we need the square root of 28. The square root of 28 is 5.3 cm.

Your final answer is 5.3 cm.
8 0
2 years ago
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