So the perimeter(P) of a rectangle would be: P= 2L+2W L being the length and W being the width. The problem says the length is 4cm more than the width, so L= 4+W. So if we substitute L with 4+W, we get: P= 2(4+W) + 2W Use the Distributive Property P= 8+2W+2W Combine like terms P=8+4W Since we're given the perimeter, we could replace P with 52. So: 52=8+4W Subtract 8 to both sides 44=4W Divide 4 to both sides 11=W Therefore, the width is 11cm And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm Thus, the dimensions of the rectangle are 15cm by 11cm
