Answer:
Check pdf
Step-by-step explanation:
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
No solution is posible from the information provided
Step-by-step explanation:
A) 2x +3
Plug in the x
2(4.1) + 3
8.2+ 3= 11.2
A is 11.2
B) 16-5y
Plug in the y
16 - 5(2.3)
16- 11.5= 4.5
B is 4.5
C) x+y
Plug in x and y
4.1 + 2.3= 6.4
C is 6.4
Answer: 25
explanation:
7² + 24² = c²
49 + 576 = c²
625 = c²
c = √625
c= 25
or just know some pythagorean triples
