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3 years ago

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Which of the following could be an example of a function with a domain [a, infinity) and a range [b, infinity) where a >0 and

b>0? Answer choices: A)f(x)= 3√x+a -b B) f(x)= √x-a +b C) f(x)= 3√(x-b) +a D)f(x)= √x+a -b

2 answers:

Zigmanuir [339]3 years ago

6 0

<span>The parent function here is √x. It has domain and range [0, ∞). Translating its "vertex" from (0, 0) to (a, b) will give it the desired domain and range. The translated function with the desired domain and range is ...
B) f(x)= √(x-a) +b </span>

Alecsey [184]3 years ago

3 0

Answer:

apex answer: f(x)= -sqrt x-b +a

Step-by-step explanation:

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Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =

Rainbow [258]

Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

$\sin N = 0.80$

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

$10^2 = 6^2 + LM^2$

$100 = 36 + LM^2$

Collect Like Terms

$LM^2 = 100 - 36$

$LM^2 = 64$

$LM = 8$

Solving (a): $\sin L$

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

Solving (c): $\cos L$

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

$\cos L = \frac{8}{10}$

$\cos L = 0.80$

Solving (d): $\sin N$

$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

7 0

3 years ago

The competitive advantage of small American factories such as Tolerance Contract Manufacturing lies in their ability to produce

Tom [10]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

$H_0: \sigma^{2} \leq 0.0008\\\\H_a: \sigma^{2} > 0.0008$

The testing states value is:

$\to x^2=\frac{(n-1)s^2}{\sigma^2}=32.6250$

therefor the $\rho - \ value = 0.2931$

Through out the above equation its values Doesn't rejects the H_0 value, and its sample value doesn't support the claim that although the configuration of its dependent variable has been infringed.

5 0

2 years ago

A sporting goods store has a sale on soccer balls: if you buy two soccer balls at the regular price, you get a third soccer ball

Snowcat [4.5K]

Answer:

The regular price of the balls is $8

Step-by-step explanation:

The sporting goods store sales promotion is as follows;

The price of the third ball after buying two balls at regular price = $1.00

The price of the number of balls Coach John pays for the balls he bought = $136

To buy 24 balls, we have;

2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1

Therefore;

The number of balls bought at regular price = The sum of the 2s = 16 balls

The number of balls bought for $1 = 24 - 16 = 8 balls

Let x represent the regular price of the balls, we have;

16 × x + 8 = 136

16·x = 138 - 8 = 128

x = 128/16 = 8

The regular price of the balls = x = $8.

7 0

2 years ago

What is the slope of a horizontal line

Step2247 [10]

Answer:

0

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Kevin is solving this problem. 737 × 205 What are the partial products Kevin will need to solve the problem? A. 3,685 and 147,40

Andrew [12]

the answer is A

700 x 5 = 3500

30 x 5 = 150

7 x 5 = 35

3500 + 150 +35 = 3685

700 x 200 = 140,000

30 x 200 = 6000

7 x 200 = 1400

140000 + 6000 + 1400 = 147400

6 0

2 years ago