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Tcecarenko [31]
2 years ago
14

Hello everyone please I need help with this question quickly!

Mathematics
1 answer:
alisha [4.7K]2 years ago
5 0

Answer:

112.93

Explanation:

\sf \boxed{\sf Mean= \frac{interval \ midpoint \ x \ frequency }{Total \ Frequency} }

Solving Stepwise:

\rightarrow \sf \dfrac{37.5 \ x \ 100 \ + \ 75 \ x  \ 45 \ + \ 125 \ x \  67 \ + \ 175 \ x  \ 50 \ + \ 225 \ x  \ 0 \ + \ 275 \ x \ 12 \ + \ 325 \ x \ 16 }{100 + 45 +67+50+0+12+16}

\rightarrow \sf \dfrac{32750}{290}

\rightarrow \sf \dfrac{3275}{29}

\rightarrow \sf 112.9310345

\rightarrow \sf 112.93 \ (rounded \ to \ nearest \ 2 \ decimal \ places)

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Use the distance formula to determine the distance between (-8,10) and (-6,7)
hjlf

Answer:

Distance: \sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where:

  • d is the distance between points (x_1,y_1) and (x_2,y_2)
  • (x_1,y_1) are the coordinates of the first point
  • (x_2,y_2) are the coordinates of the second point

We are given that:

  • (x_1,y_1)=(-8,10)
  • (x_2,y_2)=(-6,7)

To determine the value of our distance, d, we plug in our given information into the formula and solve for

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-6-(-8))^2+(7-10)^2}

d=\sqrt{(-6+8)^2+(-3)^2}

d=\sqrt{(2)^2+(-3)^2}

d=\sqrt{4+9}

d=\sqrt{13}

Therefore, the distance between (-8,10) and (-6,7) is \sqrt{13} units.

See the attached graph for a visual.

5 0
3 years ago
Which equation represents the values shown in the table?
konstantin123 [22]

Answer:

if y =50 then x = 10 ......... option d

8 0
3 years ago
Read 2 more answers
A triangle has vertices at (−4,−6),(3,3),(7,2). Rounded to two decimal places, which of the following is the closest approximati
Kryger [21]

The answer is

29.12

hope this helps

7 0
4 years ago
What is the lcm of 24de^2 and 36d^3e
lisov135 [29]
The lcm of this is 6d
7 0
4 years ago
What is the arc measure of an arc with length 4.189 cm and radius equal to 3 cm.'?
Mazyrski [523]
Given that the arc length is 4.189 cm and the radius is 3 cm, the size of the arc will found as follows;
C=theta/360 πd
suppose:
size  of arc=theta=x
d=3*2=6 cm
hence;
4.189=x/360*π*6
4.189=0.0524x
x=4.189/0.0524
x=80.004°
The size of the arc length is 80.004°
6 0
3 years ago
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