Answer:
I think it is 1 because that is all that works for me
Answer:
if(y==10)
{
x=0; // assigning 0 to x if y equals 10.
}
else
{
x=1; // assigning 1 to x otherwise.
}
Explanation:
In the if statement i have used equal operator == which returns true if value to it's right is equal to value to it's left otherwise false.By using this operator checking value of y and if it is 10 assigning 0 to x and if it is false assigning 1 to x.
Answer:
a=4 , b=1
Explanation:
I'm not a computer science major at all but I think I can help you with this code.
Our program wants us to add 2 to a get new a value while also subtracting 1 from b value to obtain new b value. We we want to for for as long b is not 0 and a/b is nonnegative.
One round we get:
New a=0+2=2
New b=3-1=2
Let's see if we can go another round:
New a=2+2=4
New b=2-1=1
We can't go another round because b would be negative while a is positive which would make a/b negative. So our loop stops at this 2nd round.
a=4 , b=1
Other notes:
2nd choice makes no sense because a is always going to increase because of the addition on a and b was going to decrease because of the subtraction on it.
Third choice makes no sense because a/b doesn't even exist.
Fourth choice a/b is negative not nonnegative.
Answer:
product_name = input("Enter product name : ")
if product_name=="pen"or"book"or"box"or"pencil"or"eraser":
if product_name == "pen":
amount = 10
print(f"Product Name: {product_name}\nCost: {amount} rupees")
if product_name == "book":
amount = 100
print(f"Product Name: {product_name}\nCost: {amount} rupees")
if product_name == "box":
amount = 150
print(f"Product Name: {product_name}\nCost: {amount} rupees")
if product_name == "pencil":
amount = 5
print(f"Product Name: {product_name}\nCost: {amount} rupees")
if product_name == "eraser":
amount = 8
print(f"Product Name: {product_name}\nCost: {amount} rupees")
else:
print("Item not found!")
Explanation:
The python program is a code of nested if-statements that compares the input string to five items of the first if-statement. For every item found, its code block is executed.
Answer:
I don't know the language this is but here is something that will work for all lang
int num0 = 0;
int num1 = 0;
basically just print the ints in the right dimension
Explanation:
Sorry if I am wrong
I don't know much about this someone else's answer might be better than mine
