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nignag [31]
2 years ago
10

Solve the addition equation by finding a common multiple. One third plus four sixths plus six eighteenths equals blank

Mathematics
2 answers:
kirza4 [7]2 years ago
6 0
Answer: c


Explanation: it’s c I’m pretty sure
Oliga [24]2 years ago
5 0
C bc a common multiple is eighteen and you multiply each of those
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Which value of b would make x²+bx-30 factorable?<br> A. -31<br> B. -17<br> C. 11<br> D. 13
dimulka [17.4K]

Answer:

D. 13

Step-by-step explanation:

well since it's a quadratic equation, it can be written in the form of ax²+bx+c=0. So we have a=1, b=b and c= -30. Also the roots are given by the equation-

x= -b±\sqrt{b^{2}-4ac} /2a. So all I did was put the number from the choices which would satisfy the sqrt part and that turned out to be 13 since \sqrt{13^{2}-4*1*(-30) = \sqrt{289} = 17. So b=13.

5 0
3 years ago
Read 2 more answers
Y+7=19y -3 <br><br> ayuda .prometo dar mucho amor
Vladimir79 [104]

Answer:

y = 0.55 or 5 / 9

Step-by-step explanation:

here's the solution :-

=》y + 7 = 19y - 3

=》7 + 3 = 19y - y

=》18y = 10

=》y = 10 ÷ 18

=》y = 5 ÷ 9

=》y = 0.55

6 0
2 years ago
Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2
fredd [130]

Answer:

Both get the same results that is,

\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

Step-by-step explanation:

Given :

\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

and initial population,

\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]

a) - After two times, we will find in each position.

P_2=[P].[M]^2=[P].[M].[M]

M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

     =\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]

b) - With in migration process, 500 people are numbered. There will be after a long time,

After\;inifinite\;period=[M]^n.[P]

Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

                                   =\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

4 0
3 years ago
PLEASE HELP THIS IS DUE BY TOMORROW
Bezzdna [24]

Answer:b

Step-by-step explanation:

4 0
3 years ago
Calculate the distance between (0,3) and (3,10) to 1 decimal place
Artemon [7]
Alright, so the distance formula is sqrt((x1-x2)^2+(y1-y2)^2), and plugging that in, we get sqrt((0-3)^2+(3-10)^2)=sqrt((-3)^2+(-7)^2)=sqrt(9+49)=sqrt(58)=around 7.6
5 0
3 years ago
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