I attached the rest of your question in the image below.
We use the normal distribution density function f(z) to find the probability of a specific range of values.
Z= ((X-μ)/σ)
μ = 475σ = 8
a) X< 470 ml
P[X<470] = P[Z<(470-475)/8] = P[Z<(470-475)/8] = P[Z<-0.625] = 0.2659
b) 6 pack with a mean of less than 470ml
Z = ((X-μ)/(σ/√n))
Z = (470-475)/(8/√6)
P [Z<-1.53] = 0.063
c) 12 pack with a mean of less than 470ml
Z = ((X-μ)/(σ/√n))
Z = (470-475)/(8/√12)
P [Z<-2.165] = 0.0152
I believe it would be 14.368?
Hello!
We know that the formula for perimeter of a rectangle is:
P = 2l + 2w
We've been given enough information to solve this question!
The perimeter of the rectangle is 60 metres, and the its length is 14 meters long.
We must multiply the length by 2 and then subtract it from the perimeter to find the width.
W = P - 2l
W = 60 - 2(14)
W = 32
Therefore, the width of the rectangle is 32 metres long.
(7x-3y)^2 hope this helps