Answer:
0.7
Step-by-step explanation:
Given a biased dice :
Probability of landing on 6 = P(6) ;
P(6) = 0.3
Recall :
P(A') = 1 - P(A)
Therefore,
If
P(6) = 0.3
P(not landing on 6) ; P(not 6) ;
P(not 6) = 1 - P(6)
P(not 6) = 1 - 0.3 = 0.7
Hence, Probability of not landing on 6 = 0.7
A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.
Answer: The correct option is B) about 34%
Proof:
We have to find 
To find
, we need to use z score formula:
When x = 4.2, we have:


When x = 5.1, we have:


Therefore, we have to find 
Using the standard normal table, we have:
= 

or 34.13%
= 34% approximately
Therefore, the percent of data between 4.2 and 5.1 is about 34%
<span>7r²+9=1
</span><span>the equation is contradictory, just to prove
7r</span>² + 9 = 1
7r² + 9 -1 = 0
7r² + 8 = 0
<span>We write the equation in the form of products of
</span>
7 * (r² + 8/7) = 0
<span>the product is equal to 0 when one of the factors is zero
</span>
7≠0 ∨ (r² + 8/7) = 0
r² ≠ - 8/7
<span>any number squared is not negative.
</span><span>We proved that none of the factors is not equal to zero , so the right side of the equation is not equal to the left . The equation is contradictory</span>
Answer:
-1/2
Step-by-step explanation:
Data:
Apples = 28
Oranges = 20
Pears = 12
<span>What is the ratio of apples to the total pieces of fruit?
Solving:
</span>

<span>
</span>