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3 years ago

Find the sum 5.5+7.25-5.5+(-7.25) show your work

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

8 0

Answer:

5.5+7.25−5.5−7.25 = 0

Step-by-step explanation:

To be honest, you shouldn't have to show work for an equation like this. But this is the answer. Hope it helped.

kirill [66]3 years ago

3 0

Answer:

5.5+7.25-5.5+(-7.25)

step 1: add 5.5 and 7.25

12.75−5.5−7.25

step 2: subtract 5.5 from 12.75

7.25−7.25

The answer is 0.

Step-by-step explanation:

Brainliest?

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Witch is bigger 4/12 or 3/6

Debora [2.8K]

4/12 is 0.33% while 3/6 is 0.5% so 3/6 is bigger

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3 years ago

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Listed below are speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, California (based on data from SigAlert

adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

$Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12}$ $= 60.67$

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: $s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}$

Put value in formula of Standard Deviation,

$s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}}$ = 40.75

Step-3: Then, we have to find the critical value by chi-square.

$X_{1-\alpha/2}^{2}=3.82$

$X_{1-\alpha/2}^{2}=21.92$

Then, find the confidence interval which is 95%.

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9$

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9$

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3 years ago

Kon'nichiwa !!<br><br>What's the Value of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%203%20%5Ctimes%20-%20%203%7D%2

NeX [460]

Answer:

3 answer

Step-by-step explanation:

hope it helps!!!

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2 years ago

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Recent census data indicated that 14.2% of adults between the ages of 25 and 34 live with their parents. A random sample of 125

kicyunya [14]

Answer:

The probability is $P(14 < X < 20 ) = 0.5354$

Step-by-step explanation:

From the question we are told that

The proportion that live with their parents is $\r p = 0.142$

The sample size is n = 125

Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution

i.e

$X \ \~ \ B( \mu , \sigma )$

Now the mean is evaluated as

$\mu = n * \r p$

$\mu = 125 * 0.142$

$\mu = 17.75$

Generally the proportion that are not staying with parents is

$\r q = 1 - \r p$

= > $\r q = 0.858$

The standard deviation is mathematically evaluated as

$\sigma = \sqrt{n * \r p * \r q }$

$\sigma = \sqrt{ 125 * 0.142 * 0.858 }$

$\sigma = 3.90$

Given the n is large then we can use normal approximation to evaluate the probability as follows

$P(14 < X < 20 ) = P( \frac{ 14 - 17.75}{3.90}$

Now applying continuity correction

$P(14 < X < 20 ) = P( \frac{ 13.5 - 17.75}{3.90} < \frac{ X - \mu }{\sigma } < \frac{ 19.5 - 17.75}{3.90} )$

Generally

$\frac{ X - \mu }{\sigma } = Z ( The \ standardized \ value \ of X )$

$P(14 < X < 20 ) = P( \frac{ 13.5 - 17.75}{3.90} < Z< \frac{ 19.5 - 17.75}{3.90} )$

$P(14 < X < 20 ) = P( -1.0897 < Z< 0.449 } )$

$P(14 < X < 20 ) = P( Z< 0.449 ) - P(Z < -1.0897)$

So for the z - table

$P( Z< 0.449 ) = 0.67328$

$P(Z < -1.0897) = 0.13792$

$P(14 < X < 20 ) = 0.67328 - 0.13792$

$P(14 < X < 20 ) = 0.5354$

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3 years ago

What is the solution set? Enter your answer in the box

Xelga [282]

Answer:

$x>3$

The solution set is $(3, infinite)$

Step-by-step explanation:

we have

$5.5x+15.5>32$

Solve for x

Subtract $15.5$ both sides

$5.5x+15.5-15.5>32-15.5$

$5.5x>16.5$

Divide by $5.5$ both sides

$5.5x/5.5>16.5/5.5$

$x>3$

The solution is the interval-------> $(3, infinite)$

All real numbers greater than $3$

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3 years ago