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3 years ago

8

Find the sum 5.5+7.25-5.5+(-7.25) show your work

2 answers:

chubhunter [2.5K]3 years ago

8 0

Answer:

5.5+7.25−5.5−7.25 = 0

Step-by-step explanation:

To be honest, you shouldn't have to show work for an equation like this. But this is the answer. Hope it helped.

kirill [66]3 years ago

3 0

Answer:

5.5+7.25-5.5+(-7.25)

step 1: add 5.5 and 7.25

12.75−5.5−7.25

step 2: subtract 5.5 from 12.75

7.25−7.25

The answer is 0.

Step-by-step explanation:

Brainliest?

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qwelly [4]

2.5 times.

40 divided by16 equals 2.5
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3 years ago

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stepan [7]

Answer:

$Area = 129.5m^2$

$Perimeter = 48m$

Step-by-step explanation:

Given

See attachment

Required

Determine the area and the perimeter of the garden

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First, we calculate the $area\ of\ the\ rectangle$

$A_1 = L * B$

Where:

$L = 20-(3.5 +3.5)$

$B = 7$

So:

$A_1 = (20 - (3.5 + 3.5)) * 7$

$A_1 = (20 - 7) * 7$

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Next, we calculate the area of the two semi-circles.

Two semi-circles = One Circle

So:

$A_2 = \pi r^2$

Where

$r = \frac{7}{2}$

$A_2 = \frac{22}{7} * (\frac{7}{2})^2$

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$A_2 = \frac{22}{1} * \frac{7}{4}$

$A_2 = \frac{22*7}{4}$

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Area of the garden is

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Calculating Perimeter

First, we calculate the perimeter of the rectangle

But in this case, we only consider the length because the widths have been covered by the semicircles

$P_1 = 2 * L$

Where:

$L = 20-(3.5 +3.5)$

So:

$P_1 =2 * (20-(3.5 +3.5))$

$P_1 =2 * (20-7)$

$P_1 =2 * 13$

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So:

$P_2 = 2\pi r$

Where

$r = \frac{7}{2}$

$P_2 = 2 * \frac{22}{7} * \frac{7}{2}$

$P_2 = \frac{2 * 22 * 7}{7 * 2}$

$P_2 = \frac{308}{14}$

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$Perimeter = P_1 + P_2$

$Perimeter = 26 + 22$

$Perimeter = 48m$

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lana [24]

Answer:

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3 years ago

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