Which answer choice shows the decimals in order from least to greatest?

The 18th term of an arithmetic sequence is 49 and the first term is 15.

Tju [1.3M]

Answer:

33

Step-by-step explanation:

49-15=34

34/17=2

For this sequence, you can write this function:

f(x)=15+2(x-1)

Check:

f(18)=15+2(18-1)

f(18)=15+2(17)

f(18)=15+34

f(18)=49

So:

f(10)=15+2(10-1)

f(10)=15+2(9)

f(10)=15+18

f(10)=33

5 0

3 years ago

Jeremiah jogged 3 3/4 miles on Saturday morning and 2 1/2 miles Saturday evening. How many miles did he jog on Saturday?

Digiron [165]

Answer:

6.25 Miles

6 1/4

Step-by-step explanation:

3 + 2 = 5 MILES

1/2 you want the denominator to equal 4 so you times it by two

= 2/4

2/4+3/4= 5/4

this gives you one full mile and 1/4

add all together 5+1+1/4

I am picking this is right :)

7 0

3 years ago

Read 2 more answers

What is the mean absolute deviation of the data set? {12, 10, 10, 8, 6, 7, 7, 12}

Simora [160]

Answer:

The MAD of {12, 10, 10, 8, 6, 7, 7, 12} is 2.

Step-by-step explanation:

Step 1 : Add all the values Up:

 $12+10+10+8+6+7+7+12=72$

Step 2 : Divide them by the number of items or numbers:

$\frac{12+10+10+8+6+7+7+12}{8}=9$

Step 3: Find the absolute deviations:

$12-9=3\\10-9=1\\10-9=1\\9-8=1\\9-6=3\\9-7=2\\9-7=2\\12-9=3\\$

Step 4: Add all the absolute deviations:

$3+1+1+1+3+2+2+3=16$

Step 5: Find the mean:

$\frac{3+1+1+1+3+2+2+3}{8}=2$

7 0

3 years ago

Let O be an angle in quadrant III such that cos 0 = -2/5 Find the exact values of csco and tan 0.

vivado [14]

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

$cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}$

$\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}$

4 0

2 years ago

Determine if the expression – 6y5 z5 – is a polynomial or not. If it is a

sasho [114]

Answer:

it is not

Step-by-step explanation:

that is where I truly believe

8 0

3 years ago