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2 years ago

Find the missing side length.

Mathematics

2 answers:

ddd [48]2 years ago

5 0

Answer:

Step-by-step explanation:

The top must be the same length as the total of the bottom

top = 5+8

top = 13

zloy xaker [14]2 years ago

5 0

13 just did it and got it right

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Please help me on 9 & 10 ! Will give you brainliest

vlabodo [156]

9. The decrease in population for Lakeside 5,500.

You can find this by taking the new amount and subtracting the original amount. This will give you the net change.

new - old = net change

45,800 - 51,300 = net change

-5,500 = net change

10. The percent increase for Riverview is +51%.

You can find that by looking at the formula for percent change.

$\frac{new - old}{old}$

$\frac{63000 - 41700}{41700}$

$\frac{21300}{41700}$

51%

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3 years ago

What is the range of the following graph????

mrs_skeptik [129]

Pretty sure it's C. The range of y goes from 0 to 4

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3 years ago

Neil has been running a tutoring business since 2005. He charges a monthly fee for weekly tutoring sessions and a phone help lin

emmainna [20.7K]

Answer:

Part A. Rate of change $ 50

The initial value of Neil's business is $ 1,200

Part B. x = 1200 + 50y

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Year Annual Tutoring Fee

2005 $ 1,200

2008 $ 1,350

2. What is the rate of change and initial value for Neil’s business? How do you know?

Rate of change = (Annual Tutoring Fee in 2008 - Annual Tutoring Fee in 2005)/(2008 - 2005)

Replacing with the values we have:

Rate of change = (1,350 - 1,200)/3

Rate of change = 150/3 = $ 50

The initial value of Neil's business is $ 1,200

3. Write an equation in slope-intercept form to represent the fees that Neil charges each year.

Let x to represent the the fees that Neil charges annually and y to represent the number of years after 2005, we have:

x = 1200 + 50y

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3 years ago

How do I solve 3 2/3 / 4 7/10

lozanna [386]

110/141

I hope this helps

have a great day

make sure you multiply by the reciprocal

4 0

3 years ago

emily paints at a constant rate. she can paint 32 square feet in 5 minutes. what area,A, in square feet, can she paint in t minu

Paha777 [63]

Answer: A(t) = (6.4 ft^2/min)*t

Step-by-step explanation:

We know that Emily paints at a constant rate, and she can paint 32 ft^2 in 5 minutes.

Then if we take the quotient of these two quantities, we will find the amount she can paint in one minute, this is:

32ft^2/5min = (32/5) ft^2/min = 6.4 ft^2/min.

Then if she paints for t minutes, the area that she can cover can be written as:

A(t) = (6.4 ft^2/min)*t

This is the linear equation we wanted to find.

3 0

3 years ago