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horsena [70]
3 years ago
9

I need answers 1-6 please!! Thank you :))

Mathematics
1 answer:
kirza4 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

Let the number be x

1.x-10

3.-8x+1

4.19x-½

5.(x+15)²

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For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?
kvv77 [185]

Answer: Option C

f(x) = x^2;\ k (x) = x ^ 2 -7

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

k (x) = f (x) + b

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

f (x) = x ^ 2

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7.

Then the function k(x) that will have its vertex 7 units below f(x) is

k (x) = x ^ 2 -7

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3 years ago
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