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horsena [70]
3 years ago
9

I need answers 1-6 please!! Thank you :))

Mathematics
1 answer:
kirza4 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

Let the number be x

1.x-10

3.-8x+1

4.19x-½

5.(x+15)²

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Below are the jersey numbers of 11 players randomly selected from a football team. Find the range, variance, and standard deviat
Aleksandr-060686 [28]

Answer:

Range = 71

Variance = 546.0

Standard Deviation = 23.4

Option A) Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

Step-by-step explanation:

We are given the following data set in the question:

33, 29, 97, 56, 26, 78, 83, 74, 65, 47, 58

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

\text{Variance} = \displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{646}{11} = 58.7

Sum of squares of differences = 5460.18

\text{Variance} = \frac{5460.18}{11} = 546.0

S.D = \sqrt{\frac{5460.18}{10}} = 23.4

Sorted Data Set: 26, 29, 33, 47, 56, 58, 65, 74, 78, 83, 97

Range = Maximum - Minimum

Range = 97 - 26 = 71

Based on the values, we can say that

Option A) Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

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