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svp [43]
2 years ago
12

Use the table below to make a scatter plot of the data pairs (years since 1960, population) PLEASE HELP

Mathematics
2 answers:
Tpy6a [65]2 years ago
7 0

Take 1960 as 0 then find out next year's

  • 1970=10
  • 1980=20
  • 1990=30
  • 2000=40
  • 2005=45
  • 2010=50

Also

Divide each population by one thousand i.e turn to decimal .

This we done to create the plot on graph easily

The graph has been attached

for the below points

  • (0,9.706)
  • (10,10.652)
  • (20,10.798)
  • (30,10.847)
  • (40,11.353)
  • (45,11.478)
  • (50,11.576)

Anna11 [10]2 years ago
6 0

Answer:

When creating a scatter plot, first decide the explanatory variable and response variable.  

<u>Explanatory variable</u> (independent variable) is along the x-axis.

<u>Response variable</u> (dependent variable) is along the y-axis.

The population number is dependent upon the year, therefore, draw the year along the x-axis and the population along the y-axis.

As the data values for the population start at 9706 thousand, it is sensible to begin the y-axis at 9000.

As the data values for the year start at 1960, it is sensible to begin the x-axis at 1950.

An appropriate x-axis : y-axis scale to use is 1 : 50

Plot the data points according to the given in the table.  
Finally, add a title for each axis.                          

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The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q
Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

\frac{\sum f}{4}=\frac{100}{4}=25

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF)_{p} = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

     =34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75

The value of first quartile is 34.75.

Q₃ is at the position:

\frac{3\sum f}{4}=\frac{3\times100}{4}=75

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF)_{p} = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

     =44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83

The value of third quartile is 44.83.

Then the inter-quartile range is:

IQR = Q_{3}-Q_{1}

        =44.83-34.75\\=10.08

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}

                                 =\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0
3 years ago
In a large county in Central Pennsylvania, 42% of all registered voters are Democrats and 53% are Republicans. What is the proba
AVprozaik [17]

Answer:

Probability [Randomly selected voter affiliated with other party] = 1/20

Step-by-step explanation:

Given:

Percentage of Democrats voters = 42%

Percentage of Republican voters = 53%

Find:

Probability [Randomly selected voter affiliated with other party]

Computation:

Percentage of other party voters = 100% - [Percentage of Democrats voters + Percentage of Republican voters]

Percentage of other party voters = 100% - [42% + 53%]

Percentage of other party voters = 100% - 95%

Percentage of other party voters = 5%

Probability [Randomly selected voter affiliated with other party] = Percentage of other party voters / 100%

Probability [Randomly selected voter affiliated with other party] = 5% / 100%

Probability [Randomly selected voter affiliated with other party] = 1/20

8 0
2 years ago
The number represented by x is less than 7 and is evenly divisible by both 0.6 and 2.4
svetoff [14.1K]
2.4<7
2.4 / 0.6 = 4
2.4 / 2.4 = 1

4.8<7
4.8 / 0.6 = 8
4.8 / 2.4 = 2

6 0
3 years ago
7(3x + 5y)<br> Simplify this expression please!
lbvjy [14]

Answer:

21x + 35y

Step-by-step explanation:

Distribute the 7 to everything in the parentheses.

7*3=21

7*5=35

5 0
3 years ago
Read 2 more answers
What is the quotient of 2 1/5 ÷ 6 3/5 <br><br>A. 1/3<br><br>B. 3/4<br><br>C. 24/35<br><br>D. 2/3​
zepelin [54]

Answer:

A.1/3

Step-by-step explanation:

on the picture

if it's helpful ❤❤❤

THANK YOU.

7 0
2 years ago
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