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svp [43]
2 years ago
12

Use the table below to make a scatter plot of the data pairs (years since 1960, population) PLEASE HELP

Mathematics
2 answers:
Tpy6a [65]2 years ago
7 0

Take 1960 as 0 then find out next year's

  • 1970=10
  • 1980=20
  • 1990=30
  • 2000=40
  • 2005=45
  • 2010=50

Also

Divide each population by one thousand i.e turn to decimal .

This we done to create the plot on graph easily

The graph has been attached

for the below points

  • (0,9.706)
  • (10,10.652)
  • (20,10.798)
  • (30,10.847)
  • (40,11.353)
  • (45,11.478)
  • (50,11.576)

Anna11 [10]2 years ago
6 0

Answer:

When creating a scatter plot, first decide the explanatory variable and response variable.  

<u>Explanatory variable</u> (independent variable) is along the x-axis.

<u>Response variable</u> (dependent variable) is along the y-axis.

The population number is dependent upon the year, therefore, draw the year along the x-axis and the population along the y-axis.

As the data values for the population start at 9706 thousand, it is sensible to begin the y-axis at 9000.

As the data values for the year start at 1960, it is sensible to begin the x-axis at 1950.

An appropriate x-axis : y-axis scale to use is 1 : 50

Plot the data points according to the given in the table.  
Finally, add a title for each axis.                          

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Help asap.brainliest and 100 points
attashe74 [19]

Answer:

1783

Step-by-step explanation:

5 0
3 years ago
HELP FAST PLEASE!!!!!
lidiya [134]

Alright, lets get started.

The answer Sandra got is correct that is zero but there are some mistakes she made while writing steps.

2 cot(\frac{-9\pi}{2})  =  2 cot(\frac{9\pi}{2}) Incorrect step

Because as per even/odd identity,

Cot (-Θ) = - cot (Θ)

Hence

2 cot (\frac{-9\pi}{2}) = - 2 cot (\frac{9\pi}{2})

Now,

It could be written as

-2 cot (\frac{9\pi}{2}) =   -2 cot (\frac{\pi}{2})


-2 * 0

0

Hence the answer is 0. : Answer

Hope it will help :)

3 0
3 years ago
Is the following relation a function ? S = {(1,2),(2,2),(-2,2)} justify your answer
elena55 [62]

Answer:

<h3>               YES</h3>

Step-by-step explanation:

relation is a function if we have y for every x from domain and for one x we have one and only one y

x = 1  --> y = 2

x = 2 --> y = 2

x = -2 --> y = 2

no x-es without y-es

and no two the same x-es with one y

so this relation is a function

6 0
3 years ago
I really need help, please and thank you
Citrus2011 [14]
I think it’s (A) I’m not sure...sorry if it’s wrong
7 0
4 years ago
Circle 1, Circle 2, and Circle 3 have the same center and have radii, respectively, of r₁ cm, r₂ cm, r₃ cm, where r₁ &lt; r₂ &lt
ira [324]

Answer:

a) A₁ /A₂  =  r₁² / (r₂²   - r₁²)

b) A₂ /A₃  = (r₂²   - r₁²) / (r₃²   - r₂²)

Step-by-step explanation:

We have Circle 1  and area  A₁  

Area of circle 2 outside circle 1     =  A₂

Area of circle 3 outside circle 2    = A₃

On the other hand we have

A₁  = π*r₁²   area of circle 1

A₂´ =  π*r₂² area of circle 2

A₃´ = π*r₃²  area of circle 3

All areas in cm²

a) A₁ /A₂        

A₁  =  π*r₁²

According to problem statement  A₂  = π*r₂²  -   A₁

A₂  =  π*r₂²  -   π*r₁²      ⇒         A₂  =  π* (r₂²   - r₁²)

Then  A₁ /A₂  =   π*r₁² / [π* (r₂²   - r₁²)]

A₁ /A₂  =  r₁² / (r₂²   - r₁²)

b)  A₂ /A₃        

A₂  =   π* (r₂²   - r₁²)

And

A₃   =  π* (r₃²   - r₂²)

Therefore

A₂ /A₃  =   π* (r₂²   - r₁²) / π* (r₃²   - r₂²)  ⇒  A₂ /A₃  = (r₂²   - r₁²) / (r₃²   - r₂²)

A₂ /A₃  = (r₂²   - r₁²) / (r₃²   - r₂²)

6 0
3 years ago
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