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2 years ago

QUESTION 1 - 1 POINT

Mathematics

1 answer:

guajiro [1.7K]2 years ago

8 0

Answer + Step-by-step explanation:

the inequality by finding the boundary line, then shading the appropriate area.

y > − 5/2x − 5

(anything in shaded region)

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How many times shorter is one inch than one foot

luda_lava [24]

There are 12 inches in 1 foot, so I would assume that one inch would be 12 times shorter than one foot.

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3 years ago

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daniel earns base salary of $100.00 every week with an additional 6% commission on everything he sells if daniel sold $550.00 wo

nekit [7.7K]

He would have $133 in total

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3 years ago

Kellie and her sister Ashley are training for a race. Kellie ran 8 miles in 72 minutes. Ashley ran 12 miles in 102 minutes. (a)

AlladinOne [14]

Answer:

(a) = 0.12 miles, (b) = 4 miles (c) = 2 minutes.

Step-by-step explanation:

Given:

Kellie ran 8 miles in 72 minutes

Ashley ran 12 miles in 102 minutes.

To find :

(a) What is Kellie's minute-per-mile pace ?

(b) How far did Ashley run in 34 minutes?

Solution:

In 72 minutes Kellie runs = 8 miles

In 1 minute Kellie runs = $\frac{8}{72}$ $= \frac{1}{9}$ = $0.12$

Thus, Kellie's minute-per-mile pace = 0.12 miles per minute.

Ashley ran n 102 minutes = 12 miles

Ashley ran in 1 minute = $\frac{12}{102}$

Ashley ran in 34 minute = $\frac{12}{102} \times34 = \frac{408}{102}$ $= 4$ miles

Therefore, Ashley runs 4 miles in 34 minutes.

Kellie ran 8 miles in = 72 minutes

Kellie ran 1 mile in = $\frac{72}{8} = 9$

Kellie ran 4 mile in = $9\times4 = 36$

Ashley ran 12 miles in = 102 minutes.

Ashley ran 1 mile in = $\frac{102}{12}$

Ashley ran 4 miles in = $\frac{102}{12} \times4 = \frac{408}{12} = 34$

Thus, the difference in Kellie and Ashley's times after they ran 4 miles is,

Time taken by Kellie for 4 miles - Time taken by Ashley for 4 miles

36 - 34 = 2 minutes

Thus, the difference in Kellie and Ashley's times after they ran 4 miles is 2 minutes.

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4 years ago

A seed sprouted and grew 2/3 of a foot in 3 months. What was its rate of growth?

Alisiya [41]

Answer:

2/9 of a foot in one month / 8/3 inches in one month

Step-by-step explanation:

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3 years ago

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Find all 6 trigonometric ratios of the angle θ =7∏/ 6

aleksley [76]

Check the picture below, those are the x,y pairs or cosine, sine values pair.

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad
cos(\theta)=\cfrac{adjacent}{hypotenuse}\\\\
-------------------------------\\\\
cos\left( \frac{7\pi }{6} \right)=\cfrac{\stackrel{adjacent}{-\sqrt{3}}}{\stackrel{hypotenuse}{2}}\qquad \qquad sin\left( \frac{7\pi }{6} \right)=\cfrac{\stackrel{opposite}{1}}{\stackrel{hypotenuse}{2}}$

now, this is from the Unit Circle, and therefore the hypotenuse or radius wil be 1.

$\bf \begin{cases}
adjacent=&-\frac{\sqrt{3}}{2}\\
opposite=&\frac{1}{2}\\
hypotenuse=&1
\end{cases}\\\\
-------------------------------\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\quad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\\\\\\
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\qquad 
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\quad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}$

so, just plug in those values... hmmm lemme do the tangent, so you see the division of two fractions.

$\bf tan\left( \frac{7\pi }{6} \right)=\cfrac{sin\left( \frac{7\pi }{6} \right)}{cos\left( \frac{7\pi }{6} \right)}\implies tan\left( \frac{7\pi }{6} \right)=\cfrac{\frac{1}{2}}{-\frac{\sqrt{3}}{2}}\implies tan\left( \frac{7\pi }{6} \right)=\cfrac{1}{2}\cdot \cfrac{2}{-\sqrt{3}}$

$\bf tan\left( \frac{7\pi }{6} \right)=\cfrac{1}{-\sqrt{3}}\impliedby \textit{now, let's \underline{rationalize} the denominator}
\\\\\\
\cfrac{1}{-\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies \cfrac{\sqrt{3}}{-(\sqrt{3})^2}\implies -\cfrac{\sqrt{3}}{3}$

7 0

3 years ago