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maria [59]
2 years ago
13

I need help with question four and the instructions for the equations or just solve the systems of simultaneously equation using

the addition method for the two middle numbers 3 Y and -5 Y we must find the number to multiply the first equation by make the second equation equal to it.
Please help 50 points

Mathematics
1 answer:
Sliva [168]2 years ago
6 0

Answer:

x = 1\2 and y = 0

Step-by-step explanation:

8x + 3y = 4 * 5\3

14x - 5y = 7 * 1

40\3x + 5y = 20\3 -------- 1

14x - 5y = 7 ----------------- 2

add equation 1 and 2

82\3x = 41\3

x = <u>4</u><u>1</u><u> </u> <u>3</u>

3 * 82

x = 1\2

subtitute 1\2 for x in equation 2

14\2 - 5y = 7

7 - 5y = 7

5y = 7 - 7

y = 0\5

y = 0

thus x = 1\2 and y = 0

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A box contains 500 apples. 32% are rotten. How many rotten apples are there?
ziro4ka [17]
Lets find 32% of 500.

32/100 = .32

.32 * 500 = 160

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Is a proportional function f(x) = 5x linear? Why or why not? Explain with an example.
RideAnS [48]

Given two variables x and y, y is directly proportional to x (x and y vary directly, or x and y are in direct variation) if there is a non-zero constant k such that

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in this case k = 5/1

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What is the volume of the composite figure? A rectangular prism is positioned vertically; at the top it joins another rectangula
Phantasy [73]
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5 0
4 years ago
A web-based company has a goal of processing 95 percent of its orders on the same day they are received. If 485 out of the next
HACTEHA [7]

Answer:

The null hypothesis was rejected.

Conclusion: The proportions of orders completed on the day of receiving is more than 95%.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The proportions of orders completed on the day of receiving is not more than 95%, i.e. <em>p</em> ≤ 0.95.

<em>Hₐ</em>: The proportions of orders completed on the day of receiving is more than 95%, i.e. <em>p</em> > 0.95.

The significance level of the test is <em>α</em> = 0.025.

The sample size is, <em>n</em> = 500.

As the sample size is large, the sampling distribution of sample proportion can be approximated by the Normal distribution.

The mean and standard deviation of this distribution are:

\mu=p\\\sigma=\sqrt{\frac{p(1-p)}{n}}

The test statistic is:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}} }

The sample proportion is:

\hat p=\frac{X}{n}=\frac{485}{500}=0.97

Compute the test statistic as follows:

z=\frac{0.97-0.95}{\sqrt{\frac{0.95(1-0.95)}{500}} }=2.05

The decision rule is:

If the <em>p</em>-value is less than the significance level <em>α</em> then the null hypothesis is rejected.

Compute the <em>p</em>-value as follows:

p-value=P(Z>2.05)\\=1-P(Z

*Use a <em>z</em>-table.

The <em>p</em>-value = 0.0202 < <em>α</em> = 0.025.

The null hypothesis will be rejected.

<u>Conclusion</u>:

As the null hypothesis was rejected at 2.5% level of significance, it can be concluded that the proportions of orders completed on the day of receiving is more than 95%.

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3 years ago
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