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1 year ago

13

I need help with question four and the instructions for the equations or just solve the systems of simultaneously equation using

the addition method for the two middle numbers 3 Y and -5 Y we must find the number to multiply the first equation by make the second equation equal to it.
Please help 50 points

1 answer:

Sliva [168]1 year ago

6 0

Answer:

x = 1\2 and y = 0

Step-by-step explanation:

8x + 3y = 4 * 5\3

14x - 5y = 7 * 1

40\3x + 5y = 20\3 -------- 1

14x - 5y = 7 ----------------- 2

add equation 1 and 2

82\3x = 41\3

x = <u>4</u><u>1</u><u> </u> <u>3</u>

3 * 82

x = 1\2

subtitute 1\2 for x in equation 2

14\2 - 5y = 7

7 - 5y = 7

5y = 7 - 7

y = 0\5

y = 0

thus x = 1\2 and y = 0

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Which means = d-0.2

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3 years ago

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3 years ago

Simplify the expression.<br> (x 3/2)6

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For this case we must simplify the following expression:

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2 years ago

A cylindrical pressure vessel has a height of 9 feet and a diameter of 6 feet. how much gas can the pressure vessel hold when fu

bezimeni [28]

Step-by-step explanation:

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8 0

1 year ago

Find out the answers to this

meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

$\sin \theta = - 0.196$

Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

Now, $\cot \theta = - 5$

⇒ $\tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5}$ (Answer)

We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

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3 years ago