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2 years ago

PLEASE HELP!!!!!!!!!!!!!!

Mathematics

1 answer:

ohaa [14]2 years ago

3 0

In a circle, the arc is two times the length of the angle.

EFG = 98°

98 x 2 = 196

Minor arc EG = 196°

Hopefully this helps :)

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Bacteria usually reproduce by a process called binary fission. In this type of reproduction, one bacterium divides to

Fed [463]

Answer:

$\large \boxed{\text{0.0462 min}^{-1}}$

Step-by-step explanation:

One formula for the reproduction of bacteria is

$\dfrac{N}{N_{0}} = e^{kt}$

Data:

N = 2

N₀ = 1

t = 15 min

Calculation:

$\begin{array}{rcl}\dfrac{N}{N_{0}}& =& e^{kt}\\\\\dfrac{2}{1}& = & e^{k\times15 \text{ min}}\\\\2 & = & e^{15k \text{ min}}\\\ln 2 & = & 15k \text{ min}\\k & = & \dfrac{\ln2 }{\text{15 min}}\\\\& = & \textbf{0.0462 min}^{\mathbf{-1}}\\\\\end{array}\\\text{The value of the constant k is $\large \boxed{\textbf{0.0462 min }^{\mathbf{-1}}}$}$

6 0

3 years ago

What is 25.0996 rounded to the nearest thousandth

madreJ [45]

Answer:

25.100

Step-by-step explanation:

The thousandth place is the third digit to the right of the decimal point - tenths is the first, hundredths is the second, thousandths is the third. Since six rounds up and both nines round up, one must round up all of the way from the fourth decimal place to the tenth decimal place.

4 0

3 years ago

2x10^-4 - 1x10^-5 show work. I got an answer of 1.9x10^-4,

oksian1 [2.3K]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------$

$\bf 2\times 10^{-4}-1\times 10^{-5}\implies 2\cdot \cfrac{1}{10^4}-1\cdot \cfrac{1}{10^5}\impliedby 
\begin{array}{llll}
\textit{using the LCD}\\
of~10^5
\end{array}
\\\\\\
\cfrac{2}{10^4}-\cfrac{1}{10^5}\implies \cfrac{(10\cdot 2)~-~(1\cdot 1)}{10^5}\implies \cfrac{20-1}{10^5}\implies \cfrac{19}{10^5}
\\\\\\
19\cdot \cfrac{1}{10^5}\implies 19\times 10^{-5}$

8 0

3 years ago

Read 2 more answers

Suppose f is an exponential function and:

Nastasia [14]

Answer: a) $b= p(1 + r)^1$ b) $c= p(1 + r)^n$ c) $d= p(1 + r)^m$ d) $b^n=c$

Step-by-step explanation:

Since f is an exponential function.

So, it is expressed as

$f = p(1 + r)^$

Here f is the present value

p is the initial value

r is the rate of growth per time period

t is the time period.

(a) b represents the 1-unit growth factor for f.

$b= p(1 + r)^1$

(b) c represents the n n-unit growth factor for f.

$c= p(1 + r)^n$

$d= p(1 + r)^m$

Write a formula that expresses c in terms of b.

Since

$b=p(1+r)^1\\\\So,\\\\b=p(1+r)^{n\times \frac{1}{n}}\\\\b=(p(1+r)^n)^{\frac{1}{n}}\\\\b=c^{\frac{1}{n}}\\\\b^n=c$

Hence, a) $b= p(1 + r)^1$ b) $c= p(1 + r)^n$ c) $d= p(1 + r)^m$ d) $b^n=c$

8 0

3 years ago

Eva, the owner of eva's second time around wedding dresses, currently has five dresses to be altered, shown in the order in whic

cupoosta [38]

To answer this question, an assumption must be made, that Eva spends 8 hours a day working. If this is the case, then Eva will complete jobs w, x, and v on day one, for a total of six hours. Since the next job (y) requires 4 hours, she will spend two hours working that day, leaving 2 more hours to go on that job. The next day she will spend 2 hours finishing job y, completing it, and finish the longest job z (hours) that day. This means she had 4 jobs on day one, and 2 jobs on day 2 for and average of 3 jobs per day.
This answer assumes an 8 hour work day, and that Eva can start a job she cannot finish that day.

5 0

3 years ago