What is 2(2x-5)=6x+4

C bisects AB. If AC = 8x - 1 and BC = 4x + 19, what is the length of AB?

The length of AB is 78 units.

<h3>What is a Line Segment?</h3>

A line segment is defined as a measured path between two places. Line segments can make up any polygon's sides because they have a set length.

The figure is given below shows a line segment AB , where the length of line segment AB refers to the distance between its endpoints, A and B.

Given that C is the midpoint of AB

AC = 8x - 1 and BC = 4x + 19,

A______________C______________B

⇒ AB = AC+ BC

Since C is the bisects of AB, So AC = BC

⇒ AB = AC+ BC

⇒ AB = 2AC

Substitute the values of If AC = 8x - 1 and BC = 4x + 19,

⇒ 8x - 1 = 4x + 19,

Rearranging the terms in the above equation,

⇒ 8x - 4x = 1 + 19,

⇒ 4x = 20,

⇒ x = 20/4,

⇒ x = 5

So AB = 2AC

⇒ AB = 2(8x - 1) = 16x -2

Substitute the value of x = 5 in the above equation,

⇒ AB = 16(5) -2

⇒ AB = 78

Hence, the length of AB is 78 units.

Learn more about the line segment here:

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8 0

1 year ago

Find the product of all positive divisors of 288.

irinina [24]

Answer:

The answer is 1.514571894×10^21.

Step-by-step explanation:

Here, the divisors of 288 are,

1,2,3,4,6,8,9,12,16,18,24,32,36,48,72,96,144,288.

now, their product =1×2×3×4×6×8×9×12×16×18×24×32×36×48×72×96×144×288

=1.514571894×10^21.

is answer. 

Hope it helps...

6 0

2 years ago

Read 2 more answers

Number 5 pleaseeeeee

Korvikt [17]

The answer is C. y= 3/2 x. You can check by multiplying 3/2 by 3, if you get 7, it is correct

6 0

3 years ago

Find the simplified product where x>=0

irinina [24]

Answer:

The last one

Step-by-step explanation:

in the second part, x2 could to pull out as x

6 0

3 years ago

Read 2 more answers

Decrease 248 by 30%

Snowcat [4.5K]

Okay this equation really says is what is 30% of 248.

So, lets convert 30% to a fraction, 3/10 which is easier to work with.

All you have to do now is get out a calculator and do 248 *3/10 (or .3) and get 74.4

So subtract 74.4 and get

173.6

8 0

2 years ago