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2 years ago

9

Drag the operations into the order in which they should be performed to evaluate the expression below. 7 × 6 ÷ ( 13 − 10 ) + 4 a

ddition division multiplication subtraction PLES HELP I WILL GIVE BRAINLYEST

2 answers:

monitta2 years ago

5 0

Answer:It's 18

Step-by-step explanation:Multiply 7 and 6 to get 42

Subtract 10 from 13 to get 3

Divide 42 by 3 to get 14

Add 14 and 4 to get 18

s2008m [1.1K]2 years ago

3 0

Answer:

18

Step-by-step explanation:

First do the ones inside the bracket (13-10)=3

Second divide 6 by the answer you get from the first part 6÷3=2

Third multiply the answer from second with 7×2=14

Then add the answer you get from the third one to 4+14=18

Mathematically

7×6÷(13-10)+4

= 7×6÷3+4

= 7×2+4

= 14+4

= 18 Answer

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ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (

harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

<em>See the image in the attachment for the referred diagram.</em>

<em />

The two triangles, triangle AEC and triangle BDC are similar triangles.
Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

<em>This implies that</em>:

AC/BC = EC/DC = AE/DB

<em><u>Given:</u></em>

$EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm$

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>

EC/DC = AE/DB

Plug in the values

$\frac{8.1}{5.4} = \frac{AE}{2.6}$

Cross multiply

$5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06$

Divide both sides by 5.4

$AE = \frac{21.06}{5.4} = 3.9 $ cm$

<u>b. </u><u>Find the length of </u><u>AB:</u>

$AB = AC - BC$

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

Plug in the values

$\frac{6.15}{BC} = \frac{8.1}{5.4}$

Cross multiply

$BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1$

Thus:

$AB = AC - BC$

Substitute

$AB = 6.15 - 4.1\\\\AB = 2.05 $ cm$

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

Learn more here:

brainly.com/question/14327552

3 0

3 years ago

Factor this completely thank you

jeka94

4(2x raise to power 2-4-7x)

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2 years ago

1/6 of 3 yards=______feet<br><br>I know I just ask one but u get 17 points so plz help I'm stuck

bulgar [2K]

In this question, first we have to see how many feets are in 1 yard .

And there are 3 feets in 1 yard.

So in 3 yards, there are 9 feets

Therefore we will get

$\frac{1}{6}*3 yards= \frac{1}{6} * 9 feet = 1.5 feet$

Therefore the answer of the given question is 1.5 feet.

3 0

3 years ago

Given the functions, f(x) =x2+x-5 and g(x)=4x2-2x+1 perform the indicated operation when applicable state the domain restriction

sashaice [31]

Your answer would be: -3x2 + 3x - 6.

I looked online to find this answer. All credits to their owners. Answer found on brainly.com/question/2825454.

This is not my answer. I'm just here to help.

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3 years ago

Find the exact value of sin(cos^-1(4/5))

boyakko [2]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2762144

_______________

Let $\mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}$

$\mathsf{0\le \theta\le\pi,}$ because that is the range of the inverse cosine funcition.

Also,

$\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}$

Square both sides and apply the fundamental trigonometric identity:

$\mathsf{(5\,cos\,\theta)^2=4^2}\\\\
\mathsf{5^2\,cos^2\,\theta=4^2}\\\\
\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{25\cdot (1-sin^2\,\theta)=16}$

$\mathsf{25-25\,sin^2\,\theta=16}\\\\
\mathsf{25-16=25\,sin^2\,\theta}\\\\
\mathsf{9=25\,sin^2\,\theta}\\\\
\mathsf{sin^2\,\theta=\dfrac{9}{25}}
$

$\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}$

But $\mathsf{0\le \theta\le\pi,}$ which means $\theta$ lies either in the 1st or the 2nd quadrant. So $\mathsf{sin\,\theta}$ is a positive number:

$\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\
\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>

3 0

3 years ago

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