What force is needed to move a 2 kg mass with an acceleration of 5 m/s²? force = mass X acceleration

What needs to be applied in order to change an object's momentum?

Veseljchak [2.6K]

Answer:

B

Explanation:

if you want to change an object's momentum you need to apply force to the object

3 0

3 years ago

(I) A 0.145-kg baseball pitched at 31.0 m/s is hit on a horizontal line drive straight back at the pitcher at 46.0 m/s. If the c

tangare [24]

Answer:

The force between the ball and the bat = 2233 N

Explanation:

Force: This can be defined as the product of force and its acceleration.

The S.I unit of Force is Newton (N)

F = ma .............................. Equation 1

Where F = Force , m = mass of the ball, a = acceleration of the ball.

where

a = (v-u)/t..................... Equation 2

Where v = final velocity of the ball, u = initial velocity of the ball, t = time of contact between the ball an the bat.

Given: v = 46 m/s u = - 31 m/s (it hit an horizontal line drive back at the pitcher), t = 5×10⁻³ s

Substituting these values into equation 2,

a = [46-(31)]/(5×10⁻³ )

a = 77×10³/5

a = 15.4×10³ m/s².

Also given m = 0.145 kg

Substituting into equation 1,

F = 0.145(15.4×10³ )

F = 2233 N

Thus the force between the ball and the bat = 2233 N

8 0

3 years ago

What does diatomic mean?

irina1246 [14]

di means two

and atomic means atoms

means that 2 atms

7 0

3 years ago

A 26-foot ladder is placed against a wall. If the top of the ladder is sliding down the wall at -2 feet per second (note that th

RSB [31]

Answer:

Dx/dt = 4,8 f/s

Explanation:

The ladder placed against a wall, and the ground formed a right triangle

with x and h the legs and L the hypothenuse

Then

L² = x² + h² (1)

L = 26 f

Taking differentials on both sides of the equation we get

0 = 2x Dx/dt + 2h Dh/dt (1)

In this equation

x = 10 distance between the bottom of the ladder and the when we need to find, the rate of the ladder moving away from the wall

Dx/dt is the rate we are looking for

h = ? The height of the ladder when x = 10

As L² = x² + h²

h² = L² - x²

h² = (26)² - (10)²

h² = 676 - 100

h² = 576

h = 24 f

Then equation (1)

0 = 2x Dx/dt + 2h Dh/dt

2xDx/dt = - 2h Dh/dt

10 Dx/dt = - 24 ( -2 ) ( Note the movement of the ladder is downwards)

Dx/dt = 48/10

Dx/dt = 4,8 f/s

6 0

3 years ago

You are driving home from school steadily at 95 km/h fro 130 km. It begins to rainand you slow to 65 km/h. You arrive home after

tia_tia [17]

(130km) / (95km/h) = 1.37h first part of the trip 1.37h x 95 km/h = 130km change 3hr and 20 to 3.34. 3.34h -1.37h = 1.97h 1.97h x 65 km/h = 128km. I hope this will help you out.

7 0

3 years ago