The electrons in a piece of metal will leave when the polarized magnesis effect is reppeled and heated up to a certain tempeture.
Answer:
The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m
Explanation:
Given;
coefficient of kinetic friction, μ = 0.84
speed of the automobile, u = 29.0 m/s
To determine the the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;
v² = u² + 2ax
where;
v is the final velocity
u is the initial velocity
a is the acceleration
x is the shortest distance
First we determine a;
From Newton's second law of motion
∑F = ma
F is the kinetic friction that opposes the motion of the car
-Fk = ma
but, -Fk = -μN
-μN = ma
-μmg = ma
-μg = a
- 0.8 x 9.8 = a
-7.84 m/s² = a
Now, substitute in the value of a in the equation above
v² = u² + 2ax
when the automobile stops, the final velocity, v = 0
0 = 29² + 2(-7.84)x
0 = 841 - 15.68x
15.68x = 841
x = 841 / 15.68
x = 53.64 m
Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m
Moment of inertia of N₂ molecule about an axis passing through the center of mass perpendicular to the line joining the two atoms=i=2.51 x 10⁻⁴⁷ kg m²
Explanation:
Moment of inertia= i= mr₁²+ mr₂²
m= mass of nitrogen atom=2.32 x 10⁻¹¹pg=2.32 x 10⁻²⁶ Kg
r1= r2=0.0465/2= 0.02325 nm=2.325 x 10⁻¹¹ m
so i= 2.32 x 10⁻²⁶ (2.325 x 10⁻¹¹)²+2.32 x 10⁻²⁶ (2.325 x 10⁻¹¹)²
i=2.51 x 10⁻⁴⁷ kg m²
Answer:
A) 19.994 m B) 1.750 seconds
Explanation:
We are asked about time and height at which both balls pass at the same height. So both, <em>TIME </em>and <em>HEIGHT</em> of both vertical trajectories are the same.
To find the values we use the kinematics expression for vertical motion with constant acceleration, using as the gravity acceleration -9.8 m/s2. Motion downwards is negative and upwards is positive. The reference point is the bottom of the building. The equation is as follow:
For each ball this equation is:
Since the data of the problem is using SI units, then our answers will be expressed in SI units as well. Now, we first compute part B by equaling both equations (same height) and solving for time:
With this time we can find the Height by substituting it in any equation of the balls. In this case, we use the expression of ball B
Answer:
the speed of something in a given direction
Explanation:
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