Answer:3.33x10^(-17)
Explanation:
Period=wavelength ➗ velocity
Period=1/10^8 ➗ (3x10^8)
Period=3.33x10^(-17)
Explanation:
option D
you compare the data from your experimental results to the prediction being tested
Answer:
M = 1.38 10⁵⁹ kg
Explanation:
For this problem we will use the law of universal gravitation
F = G m₁ m₂ / r²
Where G is the gravitation constant you are value 6.67 10⁻¹¹ N m2 / kg2, m are the masses and r the distance
In this case the mass of the planet is m = 3.0 10²³ kg and the mass of the start is M
Let's write Newton's second law
F = m a
The acceleration is centripetal
a = v² / r
The speed module is constant, so we can use the kinematic relationship
v = d / t
The distance remembered is the length of the circular orbit and the time in this case is called the period
d = 2π r
a = 2π r / T
Let's replace Newton's second law
G m M / r² = m (4π² r² / T²) / r
G M = 4 π² r³ / T²
M = 4 π² r³ / T² G
Let's calculate
M = 4 π² (3.0 10²³)³ / (3.4 10¹¹)² 6.67 10⁻¹¹
M = 13.82 10⁵⁸ kg
M = 1.38 10⁵⁹ kg
(a) 3000 V
For two parallel conducting plates, the potential difference between the plates is given by:
where
E is the magnitude of the electric field
d is the separation between the plates
Here we have:
is the electric field
d = 4.00 cm = 0.04 m is the distance between the plates
Substituting,
(b) 750 V
The potential difference between the two plates A and B is
Let's take plate A as the plate at 0 volts:
The potential increases linearly going from plate A (0 V) to plate B (3000 V).
So, if the potential difference between A and B, separated by 4 cm, is 3000 V, then the potential difference between A and a point located at 1 cm from A is given by the proportion:
and solving for V(1 cm) we find: