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3 years ago

7

The image above shows a block pulled across a table. The spring scale which measures in Newtons, reads the force resisting the m

otion known as __________________. A) drag force B) weight force C) gravity force D) friction force

2 answers:

Nataly [62]3 years ago

7 0

D) friction force is the answer

insens350 [35]3 years ago

6 0

The correct answer is D. friction force

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A compressed gas cylinder containing 1.50 mol methane has a volume of 3.30 L. What pressure does the methane exert on the walls

sweet-ann [11.9K]

Answer:

P=11.126 atm

Explanation:

We are given that a compressed gas cylinder containing 1.50 mol methane

Volume of methane in a gas cylinder =3.3 L

Temperature = $25^{\circ}=25+273.15=298.15 K$

We have to find the pressure exert by gas on cylinder

Using ideal gas equation

PV =nRT

Where R= gas constant=0.0821 L-atm/K mol

Substitute all given values

Then we get

$P\times 3.3=1.5\times 0.0821\times 298.15$

$P=\frac{36.717}{3.3}$

P=11.126 atm

Hence, the pressure exert by the gas on cylinder =11.126 atm

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4 years ago

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How do buildings affect fog formation? Explain.<br> Please answer ASAP. I am marking brainliest!!

Kobotan [32]

Answer:

Buildings absorb heat during the day and radiate heat at night. So, temperatures at night become warmer than normal. This warmth prevents fog formation because fog formation requires low temperatures.

Explanation:

5 0

3 years ago

1: A car traveling at 10 m acceleration uniformly at 2 m. Calculate its velocity after5 s.

s344n2d4d5 [400]

Answer:

20 m/s

Explanation:

v = u + at

v: final velocity

u: initial velocity

a: acceleration

t: time

v = 10 + 2(5)

v = 10 + 10

v = 20 m/s

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3 years ago

1 a rectangular block of steel measures 4cm * 2cm* 1.5cm. its mass is 93 .6g

damaskus [11]

Answer:

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4 years ago

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A helicopter goes straight up 500m from a landing pad. It then goes north 20m. Then it goes down 452m. a) What is the displaceme

gavmur [86]

Answer:

a

x-component $20 \ m$

y-component $500 - 452 = 48 \ m$

b

Magnitude $d = 52 \ m$

direction is $\theta = 67.4^o$

Explanation:

From the question we are told that

The first vertical distance is $y_1 = 500 \ m$

The first horizontal distance is $x = 20 \ m$

The second vertical distance is $y_2 = 452 \ m$

Generally the displacement is

x-component $20 \ m$

y-component $500 - 452 = 48 \ m$

Generally the helicopters displacement is mathematically evaluated as

$d = \sqrt{ x- component ^2 + y- component ^2 }$

$d = \sqrt{ 20t ^2 + 48 ^2 }$

$d = 52 \ m$

The direction is the angle the displacement of the helicopter makes with the horizontal which is mathematically evaluated as

$\theta = tan ^{-1}[ \frac{48}{20}]$

=> $\theta = tan ^{-1}[ 2.4 ]$

=> $\theta = 67.4^o$

3 0

3 years ago