The term used is " WORK".
I'm really sorry it's not one of the choices.
Answer:
I gonna give you the number so but you need to round 6.19047619048
Explanation:
- This is a speed formula so you would use the formula speed=distance/time
- You need to rearrange it to time=distance/speed
- So you need to divide 13m by 2.1 m/s
Answer:
The mass of the cargo is 
Explanation:
From the question we are told that
The radius of the spherical balloon is 
The mass of the balloon is
The volume of the spherical balloon is mathematically represented as

substituting values


The total mass the balloon can lift is mathematically represented as

where
is the density of helium with a value of

and
is the density of air with a value of

substituting values


Now the mass of the cargo is mathematically evaluated as


Electrons have a negative charge, so if you give away electrons, you give away negative charge, thus ending with a positive charge.