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EleoNora [17]
2 years ago
13

ANSWER ASAP PLEASE I NEED HELP!

Chemistry
1 answer:
Vadim26 [7]2 years ago
7 0

Answer:

If I remember correctly it should be B because it went from Cu^2 to Cu^0

Explanation:

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Which substance exists as a molecular compound? a sulfate ion, calcium chloride, methanol, oxygen
Viktor [21]
The substance would be:Methanol (ch40)
5 0
3 years ago
Read 2 more answers
which statement regarding the relative energies of monochromatic light with with λ = 800 nm andmonochromatic light with λ = 400
olga2289 [7]

Answer:

The correct answer is option A.

Explanation:

Energy of the photon of an electromagnetic radiation is give by Planck's equation:

E=\frac{hc}{\lambda }

Where:

h = Planck's constant

c = speed of light

\lambda = Wavelength of the photon's radiation

Energy of photon of 800 nm monochromatic light

\lambda = 800 nm=400\times 10^{-9} m

E=\frac{hc}{800 \times 10^{-9} m}

Energy per mole of photons:

E\times N_A=\frac{hc}{800 \times 10^{-9} m}\times 6.022\times 10^{23} mol^{-1}..[1]

Energy of photon of 400 nm monochromatic light

\lambda '= 400 nm=400\times 10^{-9} m

Energy per mole of photons:

E'\times N_A=\frac{hc}{400 \times 10^{-9} m}\times 6.022\times 10^{23} mol^{-1}..[2]

[1] ÷ [2]

\frac{E\times N_A}{E'\times N_A}=\frac{\frac{hc\trimes 6.022\times 10^{23} mol^{-1}}{800 \times 10^{-9} m}}{\frac{hc\times 6.022\times 10^{23} mol^{-1}}{400 \times 10^{-9} m}}

\frac{E}{E'}=\frac{1}{2}

E=\frac{1}{2}\times E'

8 0
3 years ago
Read 2 more answers
List two situations where friction could be helpful
4vir4ik [10]

When its cold outside and you rub your hands together to warm them

Stopping your car; using the brakes

5 0
3 years ago
Write the structure of the product that would be formed from the S(
prisoha [69]

Answer:The product formed on reaction with hydroxide ion as nucleophile is 2R-hexane-2-ol.

The product formed on reaction with water would be a 50:50 mixture of

2S-hexane-2-ol. and 2R-hexane-2-ol.

Explanation:

2S-iodohexane on reactiong with hydroxide ion would undergo SN² substitution reaction that is substitution bimolecular. Hydroxide ion has a negative charge and hence it is a quite good  nucleophile .

The rate of a SN² reaction depends on both the substrate and nucleophile . Here the substrate is a secondary carbon center having Iodine as a leaving group.SN² reaction  takes place here as hydroxide ion is a good nucleophile and it can attack the secondary carbon center from the back side leading to the formation of 2R-hexane-2-ol.

In a SN² reaction since the the nucleophile attacks from the back-side so the product formation takes place with the inversion of configuration.

When the same substrate S-2-iodohexane undergoes a substitution reaction with water as a nucleophile then the reaction occurs through (SN¹) substitution nucleophilic unimolecular mechanism .

The rate of a SN¹ reaction depends only on the nature of substrate and is independent of the nature of nucleophile.

The SN¹ reaction is a 2 step reaction , in  the first step leaving group leaves leading to the formation of a carbocation and once the carbocation is formed then any weaker nucleophile or even solvent molecules can attack leading the formation of products.

In this case a secondary carbocation would be generated in the first step and then water will attack this carbocation to form the product in the second step.

The product formed on using water as a nucleophile would be a racemic mixture of R and S isomers of hexane -2-ol in 50:50 ratio. The two products formed would be 2R-hexane-2-ol and 2S-hexane-2-ol.

Kindly refer the attachment for reaction mechanism and structure of products.

8 0
3 years ago
10 points get it right ADVPH
Sav [38]

Answer:

Advanced Pharmaceutics Inc

Explanation:

Advanced Pharmaceutics Inc

somehow I know this acroynom

8 0
3 years ago
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