1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
EleoNora [17]
2 years ago
13

ANSWER ASAP PLEASE I NEED HELP!

Chemistry
1 answer:
Vadim26 [7]2 years ago
7 0

Answer:

If I remember correctly it should be B because it went from Cu^2 to Cu^0

Explanation:

You might be interested in
Please help will give brainliest _______________________________________________________________________________________________
bogdanovich [222]

Answer:

What subject is this for?

Explanation:

4 0
3 years ago
What might happen if the strong force didnt exist
topjm [15]
If the strong force didn't exist, there would be nothing but hydrogen and neutrons floating in space. ... When the protons and neutrons are apart there is no strong force but when they are together to resemble a nucleus, the strong force is in action.
8 0
3 years ago
Read 2 more answers
A chemist places 2.5316 g of Na 2SO 4 in a 100 mL volumetric flask and adds water to the mark. She then pipets 15 mL of the resu
Lera25 [3.4K]

Answer:

The concentration of the most dilute solution is 0.016M.

Explanation:

First, a solution is prepared and then it undergoes two subsequent dilutions. Let us calculate initial concentration:

[Na_{2}SO_{4}]=\frac{moles(Na_{2}SO_{4})}{liters(solution)} =\frac{mass((Na_{2}SO_{4}))}{molarmass(moles(Na_{2}SO_{4}) \times 0.100L)} =\frac{2.5316g}{142g/mol\times 0.100L } =0.178M

<u>First dilution</u>

We can use the dilution rule:

C₁ x V₁ = C₂ x V₂

where

Ci are the concentrations

Vi are the volumes

1 and 2 refer to initial and final state, respectively.

In the first dilution,

C₁ = 0.178 M

V₁ = 15 mL

C₂ = unknown

V₂ = 50 mL

Then,

C_{2}=\frac{C_{1} \times V_{1} }{V_{2}} =\frac{0.178M \times 15mL}{50mL} =0.053M

<u>Second dilution</u>

C₁ = 0.053 M

V₁ = 15 mL

C₂ = unknown

V₂ = 50 mL

Then,

C_{2}=\frac{C_{1} \times V_{1} }{V_{2}} =\frac{0.053M \times 15mL}{50mL} =0.016M

3 0
3 years ago
A student collects 25 mL of gas at 0.98 bar. What volume would this gas occupy at 1.013 bar? * 3 points 25.8 mL 24.2 mL .09 mL 3
trasher [3.6K]

Answer:

24.2 mL.

Explanation:

<em>Assuming constant temperature</em>, we can solve this problem using <em>Boyle's law</em>, which states:

  • P₁V₁=P₂V₂

Where:

  • P₁ = 0.98 bar
  • V₁ = 25 mL
  • P₂ = 1.013 bar
  • V₂ = ?

We <u>input the data</u>:

  • 0.98 bar * 25 mL = 1.013 bar * V₂

And <u>solve for V₂</u>:

  • V₂ = 24.18 mL

The closest option is the second one: 24.2 mL.

3 0
3 years ago
Select the correct answer.
AveGali [126]

Answer: your answers are between d or b

Explanation:

6 0
3 years ago
Other questions:
  • Why doesn’t vegetable oil stay dissolved in vinegar to make a salad dressing?
    9·2 answers
  • 9. Given the following balanced chemical
    15·1 answer
  • Which ion was formed by providing the second ionization energy to remove an electron?
    12·2 answers
  • NOT A SERIOUS QUESTION IM JUST EXPLORING BRAINLY.COM!!
    12·1 answer
  • What is the main reason that the bounce height decrease.
    15·1 answer
  • What prevents the expression of a recessive allele
    11·2 answers
  • A 642 mL sample of oxygen gas at 23.5°C and 795 mm Hg, is heated to 31.7°C and the volume of the gas expands to 957 mL. What is
    10·1 answer
  • How is a solution if different from other mixtures?????
    12·1 answer
  • which method would be best for separating the compounds of a mixture that is made from two diffrent liquids
    14·1 answer
  • Please answer this Q:
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!