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zloy xaker [14]
3 years ago
5

Three blocks of the same mass are placed in front of you. Block A has a volume of

Chemistry
1 answer:
Ivan3 years ago
8 0

Given :

Three block of same mass name A , B and C .

Sides of block A , B and C is 3.0 cm , 5.0 cm and 10.0 cm .

To Find :

Which block has the higher  density .

Solution :

We know , density \rho is given by :

\rho=\dfrac{M}{V}   ......1 )

Here , V is volume .

Now , volume V for cube is given :

V=a^3    .......2 )

(  Here , a is the side of cube )

Now ,form equation 1 we can see if mass remains constant then density decrease with increase in volume.

Therefore , cube with minimum side will have higher density , in this case it is 3 cm block .

Hence , this is the required solution .

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The actual number of pennies in a jar is 218. You miscounted and came up with 215 pennies. What is your percent error?
Katyanochek1 [597]

Answer:

3%

Explanation:

Substract the actual error from the final and multiply by 100

6 0
3 years ago
A Bronsted-Lowry base is defined as a substance that
ICE Princess25 [194]

Answer:

Accepts Protons into it.

Explanation

7 0
3 years ago
How much aluminum oxide are produced when 46.5g of Al react with 165.37g of MnO?
solong [7]

Aluminum oxide produced : = 79.152 g

<h3>Further explanation</h3>

Given

46.5g of Al

165.37g of MnO

Required

Aluminum oxide produced

Solution

Reaction

2 Al (s) + 3 MnO (s) → 3 Mn (s) + Al₂O₃ (s)

  • mol Al(Ar = 27 g/mol) :

mol = mass : Ar

mol = 46.5 : 27

mol = 1.722

  • mol MnO(Ar=71 g/mol) :

mol = 165.37 : 71

mol = 2.329

mol : coefficient ratio Al : MnO = 1.722/2 : 2.329/3 = 0.861 : 0.776

MnO as a limiting reactant(smaller ratio)

So mol Al₂O₃ based on MnO as a limiting reactant

From equation , mol Al₂O₃ :

= 1/3 x mol MnO

= 1/3 x 2.329

= 0.776

Mass Al₂O₃ (MW=102 g/mol) :

= 0.776 x 102

= 79.152 g

7 0
3 years ago
I have no clue how to do this. If someone could answer all or a few questions i would really appreciate it
yarga [219]
It’s kind of difficult to explain without being with you in person but try looking up videos on YouTube as they tend to be extremely helpful. Don’t give up on the videos right away though, keep watching it over and over until you understand. Also try to find a teacher or a smart friend to help to if you still don’t understand. I recommend getting a tutor if you require long term help. Best of luck in your studies!!
5 0
3 years ago
What are the spectator ions in Na+ + OH + H+ + Cl → H2O + Na+ + Cl?
dexar [7]

Answer:

h200

Explanation:

5 0
3 years ago
Read 2 more answers
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