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ICE Princess25 [194]
3 years ago
6

Clouds that form at an elevation of 3 kilometers will

Chemistry
1 answer:
nordsb [41]3 years ago
3 0
A.) Raindrops I believe
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The answer ............................:
Oduvanchick [21]
3.22 jk sorry idk hehehe
7 0
3 years ago
1.
garik1379 [7]

Explanation:

1.

Given parameters:

Frequency of the radiation  = 8.4 x 10¹⁴Hz

Unknown:

Energy of the wave  = ?

Solution:

The energy of a wave is given by the expression below;

    E  = hf

E is the energy

h is the Planck's constant = 6.63 x 10⁻³⁴m²kg/s

f is the frequency

 Now insert the parameters and solve;

 E  =  6.63 x 10⁻³⁴m²kg/s x 8.4 x 10¹⁴Hz

 E  = 5.57 x 10¹ x 10⁻²⁰J

 E  = 5.57 x 10⁻¹⁹J

   

2.

Given parameters:

Wavelength = 2.13 x 10⁻¹³m

Unknown:

Frequency of the wave = ?

Solution:

The frequency of a wave can be determined using the expression;

     C  = f∧

C is the speed of light = 3 x 10⁸m/s

f  is the frequency

∧ is the wavelength

      f  = \frac{C}{wavelength}   = \frac{3  x 10^{8} }{2.13 x 10^{-13} }   = 1.41 x 10²¹hz

5 0
3 years ago
When the pressure that a gas exerts
Ronch [10]

Answer:

The pressure changes from 2.13 atm to 1.80 atm.

Explanation:

Given data:

Initial pressure = ?

Final pressure = 1.80 atm

Initial temperature = 86.0°C (86.0 + 273 = 359 K)

Final temperature = 30.0°C (30+273 =303 K)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

P₁ = P₂T₁ /T₂

P₁ = 1.80 atm × 359 K / 303 K

P₁ = 646.2 atm. K /303 K

P₁ = 2.13 atm

The pressure changes from 2.13 atm to 1.80 atm.

5 0
3 years ago
Read 2 more answers
When Acid is added to the buffer, base within the buffer reacts with added
LuckyWell [14K]
F A L S E yeyeyeyeyye
3 0
2 years ago
What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The
Effectus [21]

<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}

We are given:

Mass of _{19}^{40}\textrm{K} = 39.963998 u

Mass of _{20}^{40}\textrm{Ca} = 39.962591 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(39.963998-39.962591)=0.001407u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.001407u)\times c^2

E=(0.001407u)\times (931.5MeV)    (Conversion factor:  1u=931.5MeV/c^2  )

E=1.3106MeV

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

6 0
3 years ago
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