Due to it's electronic configuration w/c is 1s2 2s2 2ps 3s1 considering the last w/c is 3s1, sodium should be in row 3 period a1.
Answer:
no of neutron = atomic mass - atomic number
Explanation:
here
atomic mass = 64
atomic number = 30
no of neutron = <span>64−30</span>
no of neutron = 34
Im sorry but Chapter 2 test chemistry doesnt sound much like a question can you be more specific thanks ik u can be more specififc!
Idk sorry I just have to answer something or brainily won’t let me ask my question
Why are you writing this as a question uh……